如何在无服务器环境变量中获取API网关url

Question

我正在开发一个无服务器框架(云形成)，我在同一个AWS区域创建了两个堆栈，每个serverless.yml(stack1，stack2)都有自己的API。如何在stack-2yml中获取stack-1( yml ) API URL。

​

Stack-1(serverless1.yml)

functions:
  tGateWay:
    handler: src/handlers/tGateWay.handler
    name: ${self:provider.stage}-tGateWay
    environment:
      first: ${self:provider.stage}-firstlambda
    events:
      - http:
          method: any
          path: /tGateway
          private: true

​

​

Stack-2(serverless2.yml)

functions:
  tModule:
    handler: src/handlers/tModule.handler
    name: ${self:provider.stage}-tModule
    environment:
      find: ${self:provider.stage}-find
      T_GATEWAY: https://xxxxxxxxx.execute-api.xxxxxxx-1.amazonaws.com/dev/tGateway

​

在T_GATEWAY中，我想访问stack-1API网关URL

提前感谢！

Answer 1

你可以使用SecretsManager，你可以像这样把它导入到你的函数中：

iamRoleStatements:
    - Effect: Allow
      Action:
        - secretsmanager:GetSecretValue

functions:
  handler.js
  myHandler:
    handler: myHandler
    environment:
      yourSecretKey: "{{resolve:secretsmanager:secretYouCreated:SecretString:yourSecretKey}}"