尝试找出一种在字符串中交换字符的方法(python)

Question

我正在尝试获取一个单词中的两个随机字符(而不是第一个或最后一个)，并交换它们。例如。word = wrod，什么=什么。然而，我的代码只是将第一个随机字母替换为第二个随机字母，而不是交换它们。有什么办法可以解决这个问题吗？

#Input
word = str(input("Please enter your word here: "))

#Processing/Functions/Output

#Only scramble if word has more than 3 letters
if len(word) > 3:
    
    #randompick picks random positions in the word 
    def randompick() :
        #Pick random positions
        pos1 = randint(1, len(word)-2) 
        pos2 = randint(1, len(word)-2)
        
        #Make sure second position isn't the same as the first
        while pos1 == pos2:
            pos2 = randint(1, len(word)-2)
        
        #assign letters to variables
        firstLetter = word[pos1]
        secondLetter = word[pos2]
        #run scramble function
        #return firstLetter, secondLetter
        
        scramble(firstLetter, secondLetter)
        
    #scramble swaps the two positions previously chosen in randompick  
    def scramble(firstLetter, secondLetter):
        scrambled_word = word.replace(firstLetter, secondLetter) #first replacement
        print (scrambled_word)
    
    #Run functions
    randompick()

else:
    print (word)

Answer 1

使用pop函数，这将记住并删除索引中的字符。将字符串转换为word first tho，如下所示。

word = ['w','o','r','d'];

print("result before swap: ", word)

randompos1 = 1
randompos2 = 2

word.insert(randompos1, word.pop(randompos2))
word.insert(randompos2, word.pop(randompos1+1))

print("result after swap: ", word)

Answer 2

你的“随机”代码看起来很好，但是问题出在你的替换代码上。我建议使用python列表切片。

firstLetter = word[pos1]
secondLetter = word[pos2]

if pos1 > pos2:
    before = word[:pos1]
    between = word[pos1 + 1:pos2]
    after = word[pos2 + 1:]
    print(before + secondLetter + between + firstLetter + after)
else:
    before = word[:pos2]
    between = word[pos2 + 1:pos1]
    after = word[pos1 + 1:]
    print(before + secondLetter + between + firstLetter + after)