winmain和简单代码的编译错误，“WinMain的先前解密”

Question

#include <stdio.h> 
#include <windows.h>
int WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nShowCmd)
{
    return(0);
}

我不熟悉C语言，当我尝试编译时，上面的代码返回以下错误：

main.c:3:5: error: conflicting types for 'WinMain'
 int WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nShowCmd)
     ^~~~~~~
In file included from c:\mingw\include\windows.h:44:0,
                 from main.c:2:
c:\mingw\include\winbase.h:1263:14: note: previous declaration of 'WinMain' was here
 int APIENTRY WinMain (HINSTANCE, HINSTANCE, LPSTR, int);

Answer 1

您应该使函数定义与库的声明相匹配。你有

int WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nShowCmd)

这需要是

int APIENTRY WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nShowCmd)

它缺少APIENTRY。