我有一个包含多个列的tibble,其中包含多个list列,我想对其执行unnest_wider操作。
df1 <- tibble(
gr = c('a', 'b', 'c'),
values1 = list(1:2, 3:4, 5:6),
values2 = list(1:2, 3:4, 5:6)
)我尝试了许多不起作用的方法,包括在col中添加一个向量
df1 %>% # unnest_wider doesn't take multiple inputs
unnest_wider(col = c(values, values2),
names_sep = c("_1", "_2"),
names_repair = "unique")并尝试使用mutate_at
df1 %>% # mutate_at doesn't send data
mutate_at(vars(values, values2),
~unnest_wider(col = .,
names_sep = c("_1", "_2"),
names_repair = "unique"))如何更宽地取消多个列的嵌套?
发布于 2020-03-24 11:18:37
我用过的答案
df1 %>%
unnest() %>%
mutate(q_name = rep(c("1", "2"), nrow(.)/2)) %>%
pivot_wider(id_cols = gr,
names_from = q_name,
values_from = values1:values2)发布于 2020-03-24 04:06:57
以下是map的一种选择
library(dplyr)
library(purrr)
map_dfc(names(df1[-1]), ~
df1 %>%
select(.x) %>%
unnest_wider(c(!!.x), names_sep=c("_1", "_2"),
names_repair = 'unique')) %>%
bind_cols(df1 %>%
select(gr), .)
# A tibble: 3 x 5
# gr values1_1 values1_2 values2_1 values2_2
#* <chr> <int> <int> <int> <int>
#1 a 1 2 1 2
#2 b 3 4 3 4
#3 c 5 6 5 6https://stackoverflow.com/questions/60820415
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