如何在没有外部递归函数的情况下解析多个嵌套的JSON键？

Question

我正在开发一个不一致的机器人，它解析API，格式化并返回数据。我需要解析嵌套键，特别是"current“、"today”、"day30“、"day90”和"day180“键，但找不到直接的方法。以下是JSON数据：

{
  "item": {
    "icon": "url_removed_for_obscurity",
    "icon_large": "url_removed_for_obscurity",
    "id": 859,
    "type": "Default",
    "typeIcon": "url_removed_for_obscurity",
    "name": "Example Item",
    "description": "Example Item Description",
    "current": {
      "trend": "neutral",
      "price": "1,210"
    },
    "today": {
      "trend": "negative",
      "price": "- 16"
    },
    "members": "true",
    "day30": {
      "trend": "negative",
      "change": "-4.0%"
    },
    "day90": {
      "trend": "negative",
      "change": "-8.0%"
    },
    "day180": {
      "trend": "negative",
      "change": "-3.0%"
    }
  }
}

这将按预期方式工作：

item_desc = '';
current_vals = ''; todays_vals = ''; day30_vals = ''; day90_vals = ''; day180_vals = ''
current_trend = ''; todays_trend = ''; day30_trend = ''; day90_trend = ''; day180_trend = '';

get_item_data = requests.get(item_endpoint).json()

for key, val in get_item_data.items():
        if(query_id == str(val['id'])):
            #print('[Debug] Found Item Through API...')
            if('description' in val):
                item_desc = str(val['description'])
                await context.send(item_desc)
            if('current' in val):
                current_vals = str(val['current'])
                await context.send(current_vals)
            if('today' in val):
                todays_vals = str(val['today'])
                await context.send(todays_vals)
            if('day30' in val):
                day30_vals = str(val['day30'])
                await context.send(day30_vals)
            if('day90' in val):
                day90_vals = str(val['day90'])
                await context.send(day90_vals)
            if('day180' in val):
                day180_vals = str(val['day180'])
                await context.send(day180_vals)
            break

和输出：

Example Item Description
{'trend': 'neutral', 'price': '1,210'}
{'trend': 'negative', 'price': '- 16'}
{'trend': 'negative', 'change': '-4.0%'}
{'trend': 'negative', 'change': '-8.0%'}
{'trend': 'negative', 'change': '-3.0%'}

我知道我需要这样做：

current_trend = ''; todays_trend = ''; day30_trend = ''; day90_trend = ''; day180_trend = '';
            if('current' in val):
                current_vals = str(val['current'])
                parse_current_vals = json.loads(current_vals)
                if('trend' in parse_current_vals.items()):
                    current_trend = str(parse_current_vals['trend'])
                    await context.send(current_trend)
etc

我希望它能简单地返回

negative

neutral

或

positive

它目前没有返回任何东西，因为我显然没有正确解析。我已经尝试了上面的许多不同的变体，但都没有效果。过去几个小时的谷歌搜索和尝试/错误让我在这里寻求建议。任何和所有的意见，欢迎和感谢。

Answer 1

就像这样

 data = {
  "item": {
    "icon": "url_removed_for_obscurity",
    "icon_large": "url_removed_for_obscurity",
    "id": 859,
    "type": "Default",
    "typeIcon": "url_removed_for_obscurity",
    "name": "Example Item",
    "description": "Example Item Description",
    "current": {
      "trend": "neutral",
      "price": "1210"
    },
    "today": {
      "trend": "negative",
      "price": "-16"
    },
    "members": "true",
    "day30": {
      "trend": "negative",
      "change": "-4.0%"
    },
    "day90": {
      "trend": "negative",
      "change": "-8.0%"
    },
    "day180": {
      "trend": "negative",
      "change": "-3.0%"
    }
  }
}
def as_float(val):
    value = val.strip()
    if value.endswith('%'):
        value = value[:-1]
    value = value.replace(',','')
    return float(value)
collected_trends = []
interesting_keys = {'day30','today','current'}
for key in interesting_keys:
    entry = data['item'][key]
    num = entry['change'] if 'change' in entry else entry['price']
    collected_trends.append([entry['trend'],as_float(num)])
print(collected_trends)

输出

[['neutral', 1210.0], ['negative', -4.0], ['negative', -16.0]]