import urllib.request
def get_site_html(url):
source = urllib.request.urlopen(url).read()
return source我正在尝试创建这个函数,但它抛出了下面的error-- HTTPError: HTTP Error 404: Not Found
请帮我弄一下这个。
发布于 2020-04-01 01:57:47
import urllib.request
req = urllib.request.Request('your link here')
with urllib.request.urlopen(req) as response:
the_page = response.read()发布于 2020-04-01 02:00:02
import urllib.request
requ = urllib.request.Request(url='')
with urllib.request.urlopen(requ) as f:
data = f.read()尝试此操作,否则可能需要随.read一起使用.decode语句
https://stackoverflow.com/questions/60956651
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