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社区首页 >问答首页 >传递到sklearn.model_selection.cross_validate时,从DataFrame中选择的要素是否具有不同的长度?

传递到sklearn.model_selection.cross_validate时,从DataFrame中选择的要素是否具有不同的长度?
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Stack Overflow用户
提问于 2020-03-25 21:40:10
回答 1查看 70关注 0票数 0

当我使用:

df_train[df_train.columns.drop('Survived')]

它会返回一个891*17数据帧。但是当我想用df_train['Survived']提取标签时,长度变为892。

这怎么会发生呢?数据帧中的所有列都具有相同的长度。当我尝试用dict(df_train)将我的数据帧转换成字典时,它还告诉我,所有列都有891个值,但'Survived‘有982个值。

我在收到错误时偶然发现了这一点。

代码语言:javascript
复制
ValueError: Found input variables with inconsistent numbers of samples: [891, 892]

尝试调用此函数时:

代码语言:javascript
复制
cv_results = model_selection.cross_validate(alg, df_train[df_train.columns.drop('Survived')], df_train['Survived'], cv=cv_split)

编辑:

我在一个循环中运行多个MLA,如下所示:(就在此代码位之前,长度相等)

代码语言:javascript
复制
MLA_predict = df_train['Survived']

cv_split = model_selection.ShuffleSplit(n_splits = 10, test_size = .3, train_size = .6, random_state = 0 ) 
row_index = 0
for alg in MLA:

    #set name and parameters
    MLA_name = alg.__class__.__name__
    MLA_compare.loc[row_index, 'MLA Name'] = MLA_name
    MLA_compare.loc[row_index, 'MLA Parameters'] = str(alg.get_params())

    #score model with cross validation: http://scikit-learn.org/stable/modules/generated/sklearn.model_selection.cross_validate.html#sklearn.model_selection.cross_validate
    cv_results = model_selection.cross_validate(alg, df_train[df_train.columns.drop('Survived')], df_train['Survived'], cv=cv_split)

    MLA_compare.loc[row_index, 'MLA Time'] = cv_results['fit_time'].mean()
    MLA_compare.loc[row_index, 'MLA Train Accuracy Mean'] = cv_results['train_score'].mean()
    MLA_compare.loc[row_index, 'MLA Test Accuracy Mean'] = cv_results['test_score'].mean()   
    #if this is a non-bias random sample, then +/-3 standard deviations (std) from the mean, should statistically capture 99.7% of the subsets
    MLA_compare.loc[row_index, 'MLA Test Accuracy 3*STD'] = cv_results['test_score'].std()*3   #let's know the worst that can happen!


    #save MLA predictions - see section 6 for usage
    alg.fit(df_train[df_train.columns.drop('Survived')], df_train['Survived'])
    MLA_predict[MLA_name] = alg.predict(df_train[df_train.columns.drop('Survived')])

    row_index+=1
EN

回答 1

Stack Overflow用户

发布于 2020-03-25 23:31:57

MLA_predict需要是一个不同的对象!

MLA_predict = df_train['Survived'].copy()

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/60850063

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