绘图饼图中的自定义文本标签

Question

我正尝试在绘图饼图中添加自定义文本。

我希望最大的份额被标记为Rank 1，第二大Rank 2，依此类推...

有没有办法使用texttemplate或其他方法来做到这一点？

import plotly.graph_objects as go
labels = list('ABCD')
values = [25,45,13,78]
fig = go.Figure(data=[go.Pie(labels=labels, values=values,
                      texttemplate=("Rank %i" % 1))])
fig.show()

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Answer 1

您需要此函数：

def get_ranks(lst, begin_with_one=False):
    srtd = sorted(lst, reverse=True)
    res = [srtd.index(x) for x in lst]
    return [x + 1 for x in res] if begin_with_one else res

import plotly.graph_objects as go
import numpy as np
labels = list('ABCD')
values = [25,45,13,78]
fig = go.Figure(data=[go.Pie(labels=labels, values=values,
                      texttemplate=[f"Rank {x}" for x in get_ranks(values, begin_with_one=True)])])
fig.show()

尽可能多地使用Python3中的f字符串-它们非常方便！

因为这只适用于唯一的列表元素，所以我创建了一个更好的索引评估器：

def map_to_index(lst1, lst2):
    """Return lst1 as indexes of lst2"""
    dct = {}
    for i, x in enumerate(lst2):
        dct[x] = dct.get(x, []) + [i]
    indexes = []
    for x in lst1:
        indexes.append(dct[x][0])
        if len(dct[x]) > 0:
            dct[x] = dct[x][1:]
    return indexes

和一个改进的get_ranks()

def get_ranks(lst, begin_with_one=False):
    srtd = sorted(lst, reverse=True)
    res = map_to_index(lst, srtd)
    return [x + 1 for x in res] if begin_with_one else res

然后它还可以与以下组件一起使用：

import plotly.graph_objects as go
import numpy as np
labels = list('ABCDEF')
values = [25,45,13,78,45,78] # with elements of same value
fig = go.Figure(data=[go.Pie(labels=labels, values=values,
                      texttemplate=[f"Rank {x}" for x in get_ranks(values, begin_with_one=True)])])
fig.show()

Answer 2

将数组传递给texttemplate有助于

import plotly.graph_objects as go
labels = list('ABCD')
values = [25,45,13,78]
fig = go.Figure(data=[go.Pie(labels=labels, values=values,
                      texttemplate=([4,2,3,'Rank 1']))])
fig.show()