对同一行上的多个实例使用grep重复整行匹配

Question

这问题的一个分支：

在搜索以下文件中的字符串“香蕉”时，我们希望分别使用1、2、3和7个行的实例1、2、3和4。grep输出的数量应该等于匹配实例的数量，同时仍然返回整行。

There is one banana here
There are two banana banana here
There are three banana banana banana here
Basically there is no limit to how many banana banana banana banana banana banana banana we can have
In fact we need not have any too!

注意:如果我们取消了输出中整行的限制，我们就有：

grep -no "banana" tempfile 

回传

1:banana
2:banana
2:banana
3:banana
3:banana
3:banana
4:banana
4:banana
4:banana
4:banana
4:banana
4:banana
4:banana

有什么想法吗？

编辑:这是预期的输出

1 There is one banana here
2 There are two banana banana here
2 There are two banana banana here
3 There are three banana banana banana here
3 There are three banana banana banana here
3 There are three banana banana banana here
4 Basically there is no limit to how many banana banana banana banana banana banana banana we can have
4 Basically there is no limit to how many banana banana banana banana banana banana banana we can have
4 Basically there is no limit to how many banana banana banana banana banana banana banana we can have
4 Basically there is no limit to how many banana banana banana banana banana banana banana we can have
4 Basically there is no limit to how many banana banana banana banana banana banana banana we can have
4 Basically there is no limit to how many banana banana banana banana banana banana banana we can have
4 Basically there is no limit to how many banana banana banana banana banana banana banana we can have

Answer 1

它不是很漂亮，但你可以用这样的

awk '{print NR, gsub(/banana/, "")' <tempfile

它通过使用awk gsub命令替换匹配模式(这里是香蕉)来工作，并返回它执行替换的次数。如果然后输出输入行号和匹配数

或多次重复输入行。

awk '{A=$0
b=gsub(/banana/, "")
for (i=1; i<=b; i++) print A
}' <tempfile