如何使用sed逆转word中的小写字符

Question

使用sed反转行中的每个单词

   Description
   -----------

   The job to do is reversing every word of a line.

   that a word is a sequence of lowercase alphabets

   Raw Input
   ---------

   112358 is a fibonacci sequence...
   a test line
   124816 1392781
   final line...

   Desired Output
   --------------

   112358 si a iccanobif ecneuqes...
   a tset enil
   124816 1392781
   lanif enil...

Answer 1

这个sed脚本将完成以下工作：

#!/usr/bin/sed

# Put a \n in front of the line and goto begin.
s/^/\n/
bbegin

# Marker for the loop.
:begin

# If after \n is a lower case sequence, copy its last char before \n and loop.
s/\n\([a-z]*\)\([a-z]\)/\2\n\1/
tbegin

# If after \n is not a lower case sequence, copy it before \n and loop.
s/\n\([^a-z]*[^a-z]\)/\1\n/
tbegin

# Here, no more chars after \n, simply remove it before printing the new line.
s/\n//

Answer 2

来自这里的教程是非常好的。样本：echo "nixcraft" | rev.对于SED部分，这里是这个链接。