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在Server 2008中生成数据轴
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Database Administration用户
提问于 2017-06-14 21:21:55
回答 1查看 517关注 0票数 1

我试图在Server 2008中创建一个数据透视表,但我得到的错误是

关键字'FOR‘附近的不正确语法

下面是示例DDL和我试图执行的查询-如何更改此查询以使其成功执行?

代码语言:javascript
复制
      Declare @House Table
  (
    studID int
    ,sID int
    ,course varchar(500)
    ,cls int
    ,lv decimal(10,2)
  )

  Insert Into @House (studID, sID, course, cls, lv) VALUES
  (52, 52, 'Remaining Metrics (14th Century)', 31, '12.5')
  ,(52, 52, 'History Of The World (Part I)', 33, '200.0')
  ,(52, 52, 'Singing Socks In The Rain (Part III)', 12, '3.5')
  ,(11, 11, 'Remaining Metrics (14th Century)', 31, '2.5')
  ,(11, 11, 'History Of The World (Part I)', 33, '1.5')
  ,(11, 11, 'Singing Socks In The Rain (Part III)', 12, '2.4')


  Select studID from @House
  PIVOT (lv FOR course IN ([Remaining Metrics (14th Century)],[History Of The World (Part I)], [Singing Socks In The Rain (Part III)])) As Drafts
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回答 1

Database Administration用户

回答已采纳

发布于 2017-06-14 21:30:09

看到预期的输出会很有帮助,但据猜测,您需要这样做:

代码语言:javascript
复制
SELECT
    studID,
    [Remaining Metrics (14th Century)],
    [History Of The World (Part I)],
    [Singing Socks In The Rain (Part III)]
FROM
    (SELECT StudID, Course, SUM(lv) AS Lv FROM @House GROUP BY StudID, Course) AS X
PIVOT
    (
    SUM(lv) FOR course IN ([Remaining Metrics (14th Century)], [History Of The World (Part I)], [Singing Socks In The Rain (Part III)])
    ) As Drafts

...if您希望在每门课程的一列中看到每个学生的"Lv“值的总和。

票数 3
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页面原文内容由Database Administration提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://dba.stackexchange.com/questions/176320

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