列表框在WordPress 3.9中返回错误的值

Question

我已经为WordPress 3.8创建了列表框，但它在新版本WordPress 3.9中不起作用。所以我编写了JavaScript代码：

(function() {
var ICONS;
var icon = function(id) {
    return '<i class="fa fa-' + id + '"></i>';
}

ICONS = ["rub", "ruble", "rouble", "pagelines", "stack-exchange", "arrow-circle-o-right", "arrow-circle-o-left", "caret-square-o-left", "toggle-left", "dot-circle-o", "wheelchair", "vimeo-square", "try", "adjust", "anchor", "archive", "arrows", "arrows-h", "arrows-v", "asterisk", "ban", "bar-chart-o", "barcode", "bars", "beer", "bell", "bell-o", "bolt", "book", "bookmark", "bookmark-o", "briefcase", "bug"]

var menuval=[];
for (var i = 0; i < ICONS.length; i++) {
    var _id = ICONS[i];
    menuval.push({text: icon( _id )+' '+_id, onclick: function(){setcontentfun(_id)} 
  });
}

tinymce.PluginManager.add("font_awesome_glyphs", function(editor, url) {
    var menucreate=editor.addButton('fontAwesomeGlyphSelect', {
        type: 'listbox',
        text: 'Icons',
        icon: false,
        values: menuval
    });
});

function setcontentfun(id) {
    alert(id);
    return false;
}
})();

因此，它创建了列表框并显示得很好，但是，当我单击菜单项时，它会提醒“图标”数组的最后一个元素，其中它很好地显示了列表框中的所有元素。那么，如何提醒列表项，我单击了该列表项？

Answer 1

经过长期的研究，我找到了解决办法，

var menuval=[];
var insertVar = function (val) {
    return function () { 
        editor.insertContent(val);
    }
};
for (var i = 0; i < SHORTCODES.length; i++) {
    var _id = SHORTCODES[i];
    var _code = SHORTCODE_EXE[i];
    var variable = insertVar(_code);
   //alert(_id+' '+ SHORTCODES[i]+' '+SHORTCODE_EXE[i]);
    menuval.push({text: _id, onclick: variable }); 
}