用Python连接四个

Question

我用Python制作了Connect 4的工作版本。我对Python非常陌生，所以它非常原始。请看一看，让我知道你的想法！

import random

board = [["." for x in range(7)] for x in range(6)]
symbol = ""
winCondition = ""
fullCols = []

def boardLogic(pick, user):
    if user == "user":
        symbol = "0"
    else:
        symbol = "X"
    if board[0][pick] != ".":
        if board[1][pick] != ".":
            if board[2][pick] != ".":
                if board[3][pick] != ".":
                    if board[4][pick] != ".":
                        if board[5][pick] != ".":
                            print("That column is full.")
                            if pick not in fullCols:
                                fullCols.append(pick)
                            fullCols.sort()
                            print fullCols
                        else:
                            board[5][pick] = symbol
                    else:
                        board[4][pick] = symbol
                else:
                    board[3][pick] = symbol
            else:
                board[2][pick] = symbol
        else:
            board[1][pick] = symbol
    else:
        board[0][pick] = symbol

def printBoard():
    for row in board:
        for val in row:
            print '{:4}'.format(val),
        print

def does_square_contain_win(i, j):
    #right_diag:  [[i,j], [i-1,j+1], [i-2,j+2], [i-3,j+3]]
    if i-3 in range(0, 6) and j+3 in range(0,5):
        if board[i][j] == "0" and board[i-1][j+1] == "0" and board[i-2][j+2] == "0" and board[i-3][j+3] == "0":
            print("******************************\nPlayer Wins\n******************************")
            quit()
    if i-3 in range(0, 6) and j+3 in range(0,5):
        if board[i][j] == "X" and board[i-1][j+1] == "X" and board[i-2][j+2] == "X" and board[i-3][j+3] == "X":
            print("******************************\nComputer Wins\n******************************")
            quit()
    #left_diag:  [[i,j], [i-1,j-1], [i-2,j-2], [i-3,j-3]]
    if i-3 in range(0, 6) and j-3 in range(0,5):
        if board[i][j] == "0" and board[i-1][j-1] == "0" and board[i-2][j-2] == "0" and board[i-3][j-3] == "0":
            print("******************************\nPlayer Wins\n******************************")
            quit()
    if i-3 in range(0, 6) and j-3 in range(0,5):
        if board[i][j] == "X" and board[i-1][j-1] == "X" and board[i-2][j-2] == "X" and board[i-3][j-3] == "X":
            print("******************************\nComputer Wins\n******************************")
            quit()
    #right: [[i,j], [i,j+1], [i,j+2], [i,j+3]]
    if j+3 in range(0, 5):
        if board[i][j] == "0" and board[i][j+1] == "0" and board[i][j+2] == "0" and board[i][j+3] == "0":
            print("******************************\nPlayer Wins\n******************************")
            quit()
    if j+3 in range(0, 5):
        if board[i][j] == "X" and board[i][j+1] == "X" and board[i][j+2] == "X" and board[i][j+3] == "X":
            print("******************************\nComputer Wins\n******************************")
            quit()
    #down:  [[i,j], [i-1,j], [i-2,j], [i-3,j]]
    if i-3 in range(0, 6):
        if board[i][j] == "0" and board[i-1][j] == "0" and board[i-2][j] == "0" and board[i-3][j] == "0":
            print("******************************\nPlayer Wins\n******************************")
            quit()
    if i-3 in range(0, 6):
        if board[i][j] == "X" and board[i-1][j] == "X" and board[i-2][j] == "X" and board[i-3][j] == "X":
            print("******************************\nComputer Wins\n******************************")
            quit()

while True:
    printBoard()

    #pick a column
    while True:
        try:
            yourPick = int(raw_input('Pick a column 0 - 6: '))
        except ValueError:
            print 'That\'s not a number!'
        else:
            if 0 <= yourPick < 6 and yourPick not in fullCols:
                break
            else:
                print 'Out of range or column full. Try again.'
    print(yourPick)
    #column logic
    boardLogic(yourPick, "user")

    #opponent randomly picks a column
    while True:
        try:
            theirPick = random.randint(0, 6)
        except ValueError:
            print 'That\'s not a number!'
        else:
            if theirPick not in fullCols:
                break
            else:
                print 'Column full!'
    print(theirPick)
    #column logic
    boardLogic(theirPick, "notUser")

    #check win conditions
    for i in range(0, 6):
        for j in range(0, 5):
            does_square_contain_win(i, j)

Answer 1

提高抽象

if board[0][pick] != ".":
    if board[1][pick] != ".":
        if board[2][pick] != ".":
            if board[3][pick] != ".":
                if board[4][pick] != ".":
                    if board[5][pick] != ".":
                        print("That column is full.")
                        if pick not in fullCols:
                            fullCols.append(pick)
                        fullCols.sort()
                        print fullCols
                    else:
                        board[5][pick] = symbol
                else:
                    board[4][pick] = symbol
            else:
                board[3][pick] = symbol
        else:
            board[2][pick] = symbol
    else:
        board[1][pick] = symbol
else:
    board[0][pick] = symbol

因此，如果第一个是空的，则分配第一个，如果第二个是空的，则分配第二个.

换句话说，您分配第一个空，让我写一些伪代码：

def boardLogic(pick, user):
    # ... Logic before (this should maybe be moved elsewhere)

    try:
        first_empty = first(lambda i: board[i][pick] == EMPTY, range(5+1))
        board[first_empty][pick] = symbol
    except StopIteration:
         print("That column is full.")
         # ... No empty space

哪里

EMPTY = '.'

和first很容易在StackOverflow上找到

在高级语言中，您应该尝试编写类似于问题的高级描述的代码，并避免使用许多链式条件。