这是我第一次尝试生产者-消费者问题(以及一般的线程操作),所以任何关于禁忌和修复的反馈都是非常感谢的!
#include <condition_variable>
std::condition_variable cv;
#include <iostream>
#include <random>
#include <mutex>
std::mutex mtx;
#include <thread>
// standard in all of my programs
void panic(const std::string &msg) {
throw std::runtime_error("Error: " + msg + "\n");
}
int count = 0, buff_size = 0;
char* buff;
int random_int(int lower_bound) {
std::random_device seed;
std::mt19937 generator(seed());
std::uniform_int_distribution<int> dist(lower_bound, std::nextafter(26, DBL_MAX));
return dist(generator);
}
char random_char(int lower_bound) {
return 'A' + (random_int(lower_bound) % 26);
}
/* Consumer
Reads characters from the buffer and prints them.
*/
void consume(int job) {
std::unique_lock<std::mutex> lck(mtx);
while (count == 0) {
cv.wait(lck);
}
/*
job + 1 = Running
job = Ready
*/
for (int i = 0; i < buff_size; i++) {
std::cout << buff[i] << std::endl;
}
count--;
}
/* Producer
Randomly generates letters at (pos > buff_size & pos <= 26),
inserts them at the next available position in the buffer,
and then prints out the lowercase form of the inputted letter.
*/
void produce(int job) {
std::unique_lock<std::mutex> lck(mtx);
for (int i = 0; i < buff_size; i++) {
buff[i] = random_char(buff_size);
std::cout << static_cast<char>(tolower(buff[i])) << std::endl;
}
count++;
cv.notify_one();
}
int main() {
int buf_size = 0;
std::cout << "The Producer-Consumer Problem (in C++11!)" << std::endl << "Enter the buffer size: ";
std::cin >> buf_size;
if (buf_size > 0 && buf_size <= 26) {
// set the buffer size
buff_size = buf_size;
buff = new char[buff_size];
}
else {
// rage quit
panic("The range must be > 0 and <= 26.");
}
std::thread production[10], processed[10];
/* Initialize the arrays */
for (int order = 0; order < buff_size; order++) {
production[order] = std::thread(produce, order);
processed[order] = std::thread(consume, order);
}
/* Join the threads to the main threads */
for (int order = 0; order < buff_size; order++) {
processed[order].join();
production[order].join();
}
}发布于 2015-09-19 21:18:03
我从@Mat的答案中修改的代码:
#include <condition_variable>
#include <iostream>
#include <random>
#include <mutex>
#include <thread>
#include <vector>
// global variables
std::condition_variable cv;
std::mutex mtx;
std::vector<char> data;
int count = 0, buff_size = 0;
char random_char() {
thread_local std::random_device seed;
thread_local std::mt19937 generator(seed());
thread_local std::uniform_int_distribution<int> dist('A', 'Z');
return static_cast<char>(dist(generator));
}
/* Consumer
Prints out the contents of the shared buffer.
*/
void consume() {
std::unique_lock<std::mutex> lck(mtx);
while (count == 0) {
cv.wait(lck);
}
for (const auto& it : data) {
std::cout << it << std::endl;
}
count--;
}
/* Producer
Randomly generates capital letters in the range of A to Z,
prints out those letters in lowercase, and then
inserts them into the shared buffer.
*/
void produce() {
std::unique_lock<std::mutex> lck(mtx);
char c = random_char();
std::cout << " " << static_cast<char>(tolower(c)) << std::endl;
data.push_back(c);
count++;
cv.notify_one();
}
int main() {
std::cout << "The Producer-Consumer Problem (in C++11!)" << std::endl << "Enter the buffer size: ";
std::cin >> buff_size;
// keep the buffer in-range of the alphabet
if (buff_size < 0) {
buff_size = 0;
}
else if (buff_size > 26) {
buff_size = 26;
}
std::thread production[26], processed[26];
// initialize the arrays
for (int order = 0; order < buff_size; order++) {
production[order] = std::thread(produce);
processed[order] = std::thread(consume);
}
// join the threads to the main threads
for (int order = 0; order < buff_size; order++) {
processed[order].join();
production[order].join();
}
std::cout << "Succeeded with a shared buffer of " << data.size() << " letters!";
}https://codereview.stackexchange.com/questions/104988
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