东正教复活节计算器

Question

我有计算正统复活节日期的代码，当我看到if-else部分时，它让我哭泣。请给出你的建议，如何使它发光(如果可能)。

我想我可以将日/月格式化为DateTime格式，但恐怕会带来更多的混乱。

通过这，它工作得很好。

来源

puts "- Hello, I'm EasterEvaluator. I can tell you when will be(or was) Easter."
puts "- Please enter the year which you'r interested in:"
year = gets.chomp.to_i
a = year % 19
b = year % 4
c = year % 7
d = (19*a+15) % 30
e = (2*b + 4*c + 6*d + 6) % 7
f = d + e
if f<=9 
    easter = 22+f
    easter = easter + 13 if year > 1918
    if easter > 31
        easter = easter - 31
        month = "April"
    else
        month = "March"
    end
else
    easter = f-9
    easter = easter + 13 if year > 1918
    if easter > 30
        easter = easter-30 
        month = "May"
    else 
        month = "April"
    end
end

puts "- In #{year}, Easter is going to be on #{easter} of #{month}."

Answer 1

完全未经测试的psuedo代码，但关键是实现f=从3月22日到东正教复活节的天数。

(* f gives Easter as the number of days since March 22 *) 

easter = f+22+(year<1918)*13 

month = "March"; # default 
if f > 31 {month="April"; day=f-31} 
if f > 61 {month="May"; day=f-61} 

你也可以发到http://codegolf.stackexchange.com