有没有更好的方法来编码这个文字冒险游戏？

Question

这是我第一次尝试一个基本的文字冒险游戏，我想知道是否有办法使它更有效率(或任何其他东西，我可以添加，以使游戏更好)。它还没有完全完成，但如果有办法使它更好，请张贴在评论。

#lets me use the exit function
import sys
#Lets me use the time function
import time
#Want to play loop

    #asks for name
name = raw_input('What is your name, adventurer? ')
print 'Nice to meet you, '+name+'. Are you ready for your adventure?'
while True:
    ready = raw_input('y/n ')
if ready == 'y':
    print 'Good, let us start our great adventure!'
    break
elif ready == 'n':
    print 'That is a real shame...' 
    time.sleep(1)
    print 'Exiting program in 5 seconds:'
    time.sleep(1)
    print '5'
    time.sleep(1)
    print '4'
    time.sleep(1)
    print '3'
    time.sleep(1)
    print '2'
    time.sleep(1)
    print '1'
    time.sleep(1)
    sys.exit('Exiting Game...')
    break
else:
    print 'That is not a valid answer... Try again'
    time.sleep(2)

#First level loop
while True:
print 'You awaken on the ground of a great forest. You can see two possible things to         do, enter the cabin to your left, or wander through the woods.'
print ' '

print 'Where do you want to go?'
FirstDecision = raw_input('cabin/woods ')
    #Cabin option
if FirstDecision == 'cabin':
    print 'You approach the door to the cabin, luckily it is unlocked.'
    Cnt = raw_input('Enter < to continue')
    print 'You open the door and walk through, only to hear a dry and shaky voice say:'
    print '\"Get out.\"'
    Cnt = raw_input('Enter < to continue')
    print 'What do you do?'
    FirstCabin = raw_input('leave/fight ')
    if FirstCabin == 'leave':
        print 'As you run out the door, the voice shoots and kills you.'
        Cnt = raw_input('Enter < to continue')
        print ' '
        FirstRetry = raw_input('Try again? (y/n)')
        if FirstRetry == 'y':
            print 'Restarting back at checkpoint...'
            time.sleep(2)
        elif FirstRetry == 'n':
            print 'That\'s a shame...'
            time.sleep(1)
            print 'Exiting program in 5 seconds:'
            time.sleep(1)
            print '5'
            time.sleep(1)
            print '4'
            time.sleep(1)
            print '3'
            time.sleep(1)
            print '2'
            time.sleep(1)
            print '1'
            time.sleep(1)
            sys.exit('Exiting Game...')
            break
    elif FirstCabin == 'fight':
        print 'You turn to where the voice came from and you bluntly say \"No.\"``

Answer 1

几件事。首先，您应该抽象出退出游戏的函数：

def exitGame():
    print 'That\'s a shame...'
    print 'Exiting program in 5 seconds:'
    for i in range(5):
        time.sleep(1)
        print(i+1)
    sys.exit('Exiting Game...')

其次，我可能会将小屋、重试等推到数组中。

DECISIONS = []
CABINS = []
CONTINUES = []

第三，我将第一级定义为一个函数，这样您就可以优雅地退出：

EXIT_MESSAGE = 'Exiting Game...'
#First level loop
while True:
    try: firstLevel()
    except SystemExit as e:
        print(str(e))
        break

最后一件事。使用打印作为函数而不是语句。也许这是个人偏好，但我发现字符串格式非常可取：

print('Nice to meet you, %s. Are you ready for your adventure?' % name)

Answer 2

在我看来，你代码的第38行有158个字符长：

print 'You awaken on the ground of a great forest. You can see two possible things to         do, enter the cabin to your left, or wander through the woods.'

以下是PEP 8中“最大线长”一节的前两句：

限制所有行最多79个字符。对于结构限制较少的长文本块(docstring或注释)，行长度应限制为72个字符。

若要将第38行拆分为源中的较短行，可以将其存储在括号内的变量中：

s1 = ('You awaken on the ground of a great forest. '
      'You can see two possible things to do, enter '
      'the cabin to your left, or wander through the woods.')

请注意，有了上面的内容，输出仍然是一行连续的文本，没有换行。