KeyPad代码到文本！

Question

给定一个字符串和一个数组作为输入，您的任务是输出输入字符串在典型的Mobile上输入时将打印的文本。在Mobile中，通过按n次按钮输入字母，其中n是字母在按钮标签上的位置。因此，22应该输出b。

规则

• Helper将包含字符映射([" ",".,!","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"])。这将给您节省一些字节。
• #符号将切换大小写。最初的情况会更低。因此，2#3应该输出aD。
• 0将添加一个空格。因此，202应该输出a a。
• 输入字符串中将有一个空格()来启动一个位于同一个数字按钮上的新字母。例如，要键入aa，输入字符串将是2 2。
• 输入字符串始终是有效的KeyPad代码，这一点得到了证实。

输入

你可以用你的语言支持的任何方式接受输入。

输出

您可以以任何想要的方式输出结果。函数return也是允许的。

测试用例

#4440555#666888330#999#66688111 -> "I Love You!"
#6#33777 7779990#222#4477744477778627777111 -> "Merry Christmas!"
#44#27 79990#66#3390#999#332777111 -> "Happy New Year!"

这是密码-高尔夫，所以以字节为单位的最短代码获胜！

Answer 1

Pyth - 31字节

新的关键东西花了我太多钱。

ss.emr!FZk@@QsedthdfndeTrb8cz\#

测试套房。

Answer 2

JavaScript ES6 -124个字节

高尔夫球：

f=h=>a=>(o=c="")+a.match(/#|(.)\1*/g).forEach(e=>e==" "?0:e=="#"?c=!c:(n=h[e[0]][e.length-1])*(o+=c?n.toUpperCase():n))?o:0;

f=h=>a=>(o=c="")+a.match(/#|(.)\1*/g).forEach(e=>e==" "?0:e=="#"?c=!c:(n=h[e[0]][e.length-1])*(o+=c?n.toUpperCase():n))?o:0;

console.log(f(["  ",".,!","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"])("#4440555#666888330#999#66688111"));
console.log(f(["  ",".,!","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"])("#6#33777 7779990#222#4477744477778627777111"));
console.log(f(["  ",".,!","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"])("#44#27 79990#66#3390999332777111"));

未高尔夫球：

f=(a,h)=>{
    //out string
    o="";
    //uppercase or lowercase (initialized as "" and then inverted in golfed version)
    c=0;
    //split it into array of instructions, which are sets of repeated characters, or # solely alone
    a.match(/#|(.)\1*/g).forEach((e)=>{
        e==" "?0:
            e=="#" ? (c=!c) : ( ()=>{ //lambda added because two statements ungolfed, multiplied in the golfed version
                    n=h[e[0]][e.length-1];
                    o+=c?n.toUpperCase():n;
                })()
    })
    return o;
}

Answer 3

JavaScript，301个字节

(a,b)=>{u="l";p=[];r="";a.split``.map((c,i)=>p.push(c!=a[i-1]?" "+c:c));p.join``.trim().replace('   ', ' ').split` `.map(l=>{if(l=="#"){u=(u=="l"?b.forEach((y,j)=>b[j]=y.toUpperCase())||"u":b.forEach((y,j)=>b[j]=y.toLowerCase())||"l")}else{if(l!="  "){r+=b[+l[0]][l.length-1]}else{r+=" "}}});return r}

f=(a,b)=>{u="l";p=[];r="";a.split``.map((c,i)=>p.push(c!=a[i-1]?" "+c:c));p.join``.trim().replace('   ', ' ').split` `.map(l=>{if(l=="#"){u=(u=="l"?b.forEach((y,j)=>b[j]=y.toUpperCase())||"u":b.forEach((y,j)=>b[j]=y.toLowerCase())||"l")}else{if(l!="  "){r+=b[+l[0]][l.length-1]}else{r+=" "}}});return r}

console.log(f("#4440555#666888330#999#66688111 ",["  ",".,!","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"]));
console.log(f("#6#33777 7779990#222#4477744477778627777111",["  ",".,!","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"]));
console.log(f("#44#27 79990#66#3390#999#332777111",["  ",".,!","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"]));

我知道这很长，但这是我所能做的最好的。