交换字母表

Question

在这个挑战中，您将“颠倒”字母表或将a-z与z-a交换。这通常被称为阿塔什密码。

因为这种转换使输出看起来像某种外语，所以您的代码需要尽可能短。

示例

abcdefghijklmnopqrstuvwxyz
zyxwvutsrqponmlkjihgfedcba

Programming Puzzles & Code Golf
Kiltiznnrmt Kfaaovh & Xlwv Tlou

Hello, World!
Svool, Dliow!

规范

• 输入可能包含多行，并且仅限于ASCII。
• 不应向输出添加额外的空白。
• 案件必须保存

主板

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body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}

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这是密码-高尔夫，所以以字节表示的最短代码将获胜

Answer 1

Pyth，8字节

XXzG)rG1

@xnor在@FryAmTheEggman的Pyth回答中提出了这种更简单的方法，然后我将其翻译为Pyth。

当只给出两个参数时，这就使用了X (翻译)的方便行为:它将从第二个参数转换为反向的第二个参数。我们首先用小写字母(G)，然后用超感知的G来做这件事。

Answer 2

C，59字节

很抱歉再次提到C，但是我有点失望，因为这里只看到了C函数。我的印象是OP在寻找一种有用的产品。

main(c){while(~(c=getchar()))putchar(isalpha(c)?c+4^31:c);}

在Ubuntu 14.04上编译，有一个简单的：

cc swalpha.c

生成的可执行文件从stdin读取任意数量的行，并将结果写入stdout。

感谢这么多其他海报的异或技巧。

Answer 3

CJam，17字节

我想帮助GamrCorps打高尔夫，他的CJam解决方案，但结果是如此不同，我决定作出单独的答案。

q'[,_el^_W%32f^er

在网上试试。

解释

q     e# Read all input.
'[,   e# Get a character range from the null byte up to and including "Z".
_el   e# Duplicate and convert to lowercase.
^     e# Symmetric set difference. Due to the lowercase operation only letters will not
      e# appear in both sets, and so we get a string with all uppercase letters followed
      e# by all lowercase letters, i.e "ABC...XYZabc...xyz".
_W%   e# Duplicate and reverse. Gives: "zyx...cbaZYX...CBA".
32f^  e# Take each character XOR 32 which swaps the case, so now we have:
      e#                               "ZYX...CBAzyx...cba"
er    e# Transliterate: substitute each character in the first string with the correspoding
      e# character in the second string.