她吹了！

Question

阿尔尔..。喂，我的马提斯！展开主帆！右舷满了！啊，感觉风吹在你的头发上！

对，我亲爱的..。我需要一点你的技能！我的船员比我自己更现代化..。我仍然更喜欢th指南针的‘th’点(更多信息见这里，Arrr.)当我的船员总是用头.我想要一种简单的方法，把这个废话变成我能理解的东西，Arrr！

我需要的是输入一个数字(小数是好的)的代码，比如“0 <= the headin' < 360”，它把答案作为最接近的指南针点！阿尔尔！

以下是一些例子：

> heading 0.1

North

> heading 11.25

North by East

> heading 22.7

North Northeast

> heading 44.99

Northeast

> heading 91

East

现在，如果你的头正好落在两个指南针的中间，我亲爱的，别担心.我期待着‘这’代码吐出Between <point 1> and <point 2>，例如，heading 5.625会说，Between North and North by East只会发生在一个头部，即H = 5.625 + 11.25(N)方程，其中H是‘headin’，N是0到31之间的整数.

两个限制.

( 1)我不想用数组来存储点或头的数据。你在欺骗我，先生，你在品尝我的过失.这是必须计算的，朱斯，就像过去的日子一样！阿尔尔！

2)最短的代码获胜，否则我会让你走在木板上.阿尔尔！

Answer 1

我花了太多的时间在这里寻宝，但这里有一个Java解决方案：

public class Aaaaarrrr {

    public static void main(String[] aaarrrgs) {

        float heading = Float.parseFloat(aaarrrgs[0]);

        final List<String> points = Arrays.asList("North",
                "North by east", "North-northeast", "Northeast by north",
                "Northeast", "Northeast by east", "East-northeast",
                "East by north", "East", "East by south", "East-southeast",
                "Southeast by east", "Southeast", "Southeast by south",
                "South-southeast", "South by east", "South", "South by west",
                "South-southwest", "Southwest by south", "Southwest",
                "Southwest by west", "West-southwest", "West by south", "West",
                "West by north", "West-northwest", "Northwest by west",
                "Northwest", "Northwest by north", "North-northwest",
                "North by west");


        float cp = heading / 360.0f * 32.0f;
        if (cp % 1 == 0.5f)
             System.out.print("Between " + points.get((int)Math.floor(cp)) + " and ");

         System.out.println(points.get(Math.round(cp)));

    }
}

如果我将上面的代码最小化并使其变得很难看，就会编辑如下：

Java，770 chars

import java.util.*;class A{public static void main(String[] r){List<String> l=Arrays.asList("North","North by east","North-northeast","Northeast by north","Northeast","Northeast by east","East-northeast","East by north","East","East by south","East-southeast","Southeast by east","Southeast","Southeast by south","South-southeast","South by east","South","South by west","South-southwest","Southwest by south","Southwest","Southwest by west","West-southwest","West by south", "West","West by north","West-northwest","Northwest by west","Northwest","Northwest by north","North-northwest","North by west");float c=Float.parseFloat(r[0])/360.0f*32.0f;if (c%1==0.5f) System.out.print("Between "+l.get((int)Math.floor(c))+" and ");System.out.println(l.get(Math.round(c)));}}

Answer 2

Python，264

n='north'
e='east'
s='south'
w='west'
b=' by '
def f(H):x,y,z=(n,e,s,w,e,s,w,n,n+e,s+e,s+w,n+w)[int(H%360/90)::4];return(x,x+b+y,x+'-'+z,z+b+x,z,z+b+y,y+'-'+z,y+b+x)[int(H%90*4/45)].capitalize()
h=input()+5.625
print h%11.25and f(h)or'Between '+f(h-1)+' and '+f(h)

这使用了维基百科页面上的资本化，并且应该适用于任何数字。

Answer 3

Arrr，336

A,R,r=int,input()/360.*32,' by #South#north#West#East#south#North#west#east#-#/#Between#and'.split('#')
a=''.join(r[A(c,16)]for c in'6A608A6928A6802A68A6808A4928A402A4A405A4958A1808A18A1805A1958A108A1A107A1957A1705A17A1707A3957A305A3A302A3927A6707A67A6702A6927A607').split('/')
if R%1==.5:print r[11],a[A(R)],r[12],
print a[A(round(R))]

谢谢@Jeen