程序总是返回true

Question

我需要创建一个代码，要求用户输入千兆赫兹、内核，并询问是否存在超线程，然后根据下面的图表打印cpu的性能(高/中/低)。我知道在Python中字符串是真实的，但我已经尝试了我能找到的所有建议来修复它！

enter image description here

giga = float(input("Enter CPU gigahertz:\n"))
core_count = int(input("Enter CPU core count:\n"))
hyper = input("Enter CPU hyperthreading (True or False):\n")

if hyper == "true" or "True":
    if giga >= 1.9 and giga < 2.4:
        if 4>core_count>=2:
            print("\nThat is a low-performance CPU.")

    elif giga >= 2.4 and giga < 2.7:
        if core_count>=4 and core_count <6:
            print("\nThat is a medium-performance CPU.")
        elif 4>core_count>=2:
            print("\nThat is a low-performance CPU.")

    elif giga >= 2.7:
        if core_count>=4 and core_count <6:
            print("\nThat is a medium-performance CPU.")
        elif core_count>=2 and core_count < 4:
            print("\nThat is a low-performance CPU.")
        elif core_count >= 6:
            print("\nThat is a high-performance CPU.")

    elif giga < 1.9 or core_count < 2:
        print("\nThat CPU could use an upgrade.")

    if core_count>=20:
    print("\nThat is a high-performance CPU.")

elif hyper == "False":
    if giga >= 2.4 and giga < 2.8:
        if core_count >= 2 and core_count < 6:
            print("\nThat is a low-performance CPU.")

    elif giga >= 2.8 and giga < 3.2:
        if core_count >= 6 and core_count < 8:
            print("\nThat is a medium-performance CPU.")
        if core_count <6:
            print("\nThat is a low-performance CPU.")

    elif giga >= 3.2:
        if core_count >= 8:
            print("\nThat is a high-performance CPU.")
        if core_count >= 6 and core_count < 8:
            print("\nThat is a medium-performance CPU.")
        if core_count <6:
            print("\nThat is a low-performance CPU.")


    elif giga < 2.4 or core_count < 2:
        print("\nThat CPU could use an upgrade.")

我的所有其他结果都是有效的，只有当输入是#如giga =2.8hyper=6hyper= false时才有效

它应该打印"medium-performance cpu“，但它可以识别true并打印高性能

Answer 1

让我们来看看你编写了什么代码，以及为什么解释器要做它正在做的事情。为了清楚起见，我将使用括号，但它们并不是绝对必要的。首先，你已经写好了。

if hyper == "true" or "True":

Python将此行解释为

if ((hyper == "true") or ("True")):

由于" True“为True (all non-empty sequences are True)，并且如果其旁边的任一语句为true，则or运算符将始终返回True，因此即使if为False，也将始终将此if语句视为True：

if ((False) or (True)): # This will evaluate to True

相反，您可以扩展您的条件：

if (hyper == "true") or (hyper == "True"):

或者，您可以省去一些重复操作，而使用字符串所具有的内置lower函数：

if (hyper.lower() = "true"):