异步上传文件

Question

我需要你对我的执业意见。我想改进它。

所需经费如下：

• RESTFUL + OWIN (SelfHosted)
• 端点-异步上传文件
• 从邮递员处向端点发出请求

好吧，这就是我得到的

对于自托管的OWIN，我遵循Microsoft文档。

自寄主

端点：

FileController.cs

    [HttpPost]
    [Route("api/v1/upload")]
    public HttpResponseMessage Post([FromUri]string filename)
    {
        var task = this.Request.Content.ReadAsStreamAsync();
        task.Wait();
        Stream requestStream = task.Result;

        try
        {
            Stream fileStream = File.Create("./" + filename);
            requestStream.CopyTo(fileStream);
            fileStream.Close();
            requestStream.Close();
        }
        catch (IOException)
        {
            throw new HttpResponseException( HttpStatusCode.InternalServerError);
        }

        HttpResponseMessage response = new HttpResponseMessage();
        response.StatusCode = HttpStatusCode.Created;
        return response;
    }

邮差：

邮递员返回状态代码201

Answer 1

看起来有点不必要的复杂，一点也不完全是异步的。您只是强迫异步调用与.Wait()同步。正确的方法是使用异步“一路向下”：

[HttpPost]
[Route("api/v1/upload")]
public async Task<HttpResponseMessage> Post([FromUri]string filename)
{
    try
    {
        using (Stream requestStream = await this.Request.Content.ReadAsStreamAsync())
        using (Stream fileStream = File.Create("./" + filename))
        {
            await requestStream.CopyToAsync(fileStream);
        }

        return new HttpResponseMessage { StatusCode = HttpStatusCode.Created };
    }
    catch (IOException)
    {
        throw new HttpResponseException(HttpStatusCode.InternalServerError);
    }
}