从树命令输出创建目录结构

Question

一些目录结构(在文本文件中)的tree命令输出很少。它看起来像是：

% cat tree.txt
.
├── grandpartest
│   └── partest
│       └── test
│           ├── empty-asciidoc-document.adoc
│           └── empty-asciidoc-document1.adoc
├── grandpartest2
│   └── partest2
│       └── test2
│           ├── empty-asciidoc-document.adoc
│           ├── empty-asciidoc-document1.adoc
│           └── empty-asciidoc-document2.adoc
├── grandpartest3
│   └── partest3
│       └── test3
│           ├── empty-asciidoc-document.adoc
│           ├── empty-asciidoc-document1.adoc
│           ├── empty-asciidoc-document2.adoc
│           └── empty-asciidoc-document3.adoc
└── tree.txt

9 directories, 10 files

有任何方法可以解析这些文本文件来创建类似的目录结构吗？

我知道我可以使用mkdir -p和touch创建这个目录结构。但是我感兴趣的主要事情是解析文本文件，以获得这些命令要使用的值。

更新1:

根据@muru的要求

% cat tree-j.txt
[{"type":"directory","name": ".","contents":[
    {"type":"directory","name":"grandpartest","contents":[
      {"type":"directory","name":"partest","contents":[
        {"type":"directory","name":"test","contents":[
          {"type":"file","name":"empty-asciidoc-document.adoc"},
          {"type":"file","name":"empty-asciidoc-document1.adoc"}
        ]}
      ]}
    ]},
    {"type":"directory","name":"grandpartest2","contents":[
      {"type":"directory","name":"partest2","contents":[
        {"type":"directory","name":"test2","contents":[
          {"type":"file","name":"empty-asciidoc-document.adoc"},
          {"type":"file","name":"empty-asciidoc-document1.adoc"},
          {"type":"file","name":"empty-asciidoc-document2.adoc"},
          {"type":"directory","name":"Untitled Folder","contents":[
          ]}
        ]}
      ]}
    ]},
    {"type":"directory","name":"grandpartest3","contents":[
      {"type":"directory","name":"partest3","contents":[
        {"type":"directory","name":"test3","contents":[
          {"type":"file","name":"empty-asciidoc-document.adoc"},
          {"type":"file","name":"empty-asciidoc-document1.adoc"},
          {"type":"file","name":"empty-asciidoc-document2.adoc"},
          {"type":"file","name":"empty-asciidoc-document3.adoc"}
        ]}
      ]}
    ]},
    {"type":"file","name":"tree.txt"},
    {"type":"file","name":"tree-j.txt"}
  ]},
  {"type":"report","directories":10,"files":11}
]

% cat tree-j.txt | parse-tree
Traceback (most recent call last):
  File "/home/blueray/_resources/dotfiles/python/parse-tree", line 18, in <module>
    process(structure)
  File "/home/blueray/_resources/dotfiles/python/parse-tree", line 10, in process
    os.mkdir(entry["name"])
FileExistsError: [Errno 17] File exists: '.'

Answer 1

解析tree的通常输出是很棘手的--它不是一些标准形式，比如CSV。像JSON这样的标准结构化格式会更好，因为每个条目至少需要编码两三条信息(名称、类型以及链接目标或目录条目等其他信息，这些信息根据文件类型的不同而有所不同)。tree -J确实提供了非常简单的JSON输出，您可以使用Python来处理它，它是默认Ubuntu安装的一部分，并且在标准库中有JSON处理：

#! /usr/bin/env python3

import json
import os
import sys

def process(entries):
    for entry in entries:
        if entry["type"] == "directory":
            os.makedirs(entry["name"], exist_ok=True) # Thanks @pLumo
            os.chdir(entry["name"])
            process(entry.get("contents", []))
            os.chdir('..')
        if entry["type"] == "file":
            with open(entry["name"], "w"): pass
        if entry["type"] == "link":
            os.symlink(entry["name"], entry["target"])

# read standard input
structure = json.load(sys.stdin)
process(structure)

这只处理目录、常规文件和链接；您需要为其他文件类型添加条件(不确定tree如何处理块设备、字符设备等)。