如何将以下内容转换为以networkd为呈现器的Netplan yaml文件?
在命令行中,这些命令工作并构建一个MTU为1476的GRE隧道。
ip tunnel add gre1 mode gre remote [x.x.x.x] local [y.y.y.y] ttl 255
ip link set gre1 up
ip addr add [z.z.z.z]/30 dev gre1其中x.x.x.x是远程GRE端点,y.y.y.y是GRE端点的私有IP,z.z.z.z是分配给本地GRE接口的地址。
尝试使用以下yaml片段定义隧道,但MTU被“忽略”并设置LAN /f MTU-24。
tunnels:
gre1:
mode: gre
local: [y.y.y.y]
remote: [x.x.x.x]
mtu: 1476
addresses:
- [z.z.z.z]/30来自各种命令的输出:
# systemctl status systemd-networkd | grep gre1
Sep 16 11:49:40 ip-y-y-y-y systemd-networkd[1283]: gre1: Cannot enable IPv6 for interface gre1: No such file or directory
Sep 16 11:49:40 ip-y-y-y-y systemd-networkd[1283]: gre1: Could not bring up interface: Address family not supported by protocol
# ip a
1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN group default qlen 1000
link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00
inet 127.0.0.1/8 scope host lo
valid_lft forever preferred_lft forever
inet6 ::1/128 scope host
valid_lft forever preferred_lft forever
2: ens5: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 9001 qdisc mq state UP group default qlen 1000
link/ether 16:74:7e:e0:07:46 brd ff:ff:ff:ff:ff:ff
inet [y.y.y.y]/24 brd [y.y.y.255] scope global dynamic ens5
valid_lft 2631sec preferred_lft 2631sec
inet6 fe80::1474:7eff:fee0:746/64 scope link
valid_lft forever preferred_lft forever
3: gre0@NONE: <NOARP> mtu 1476 qdisc noop state DOWN group default qlen 1000
link/gre 0.0.0.0 brd 0.0.0.0
4: gretap0@NONE: <BROADCAST,MULTICAST> mtu 1462 qdisc noop state DOWN group default qlen 1000
link/ether 00:00:00:00:00:00 brd ff:ff:ff:ff:ff:ff
5: erspan0@NONE: <BROADCAST,MULTICAST> mtu 1450 qdisc noop state DOWN group default qlen 1000
link/ether 00:00:00:00:00:00 brd ff:ff:ff:ff:ff:ff
6: gre1@NONE: <POINTOPOINT,NOARP> mtu 8977 qdisc noop state DOWN group default qlen 1000
link/gre [y.y.y.y] peer [x.x.x.x]
inet [z.z.z.z]/30 brd [z.z.z.255] scope global gre1
valid_lft forever preferred_lft forever发布于 2019-09-16 12:41:58
尴尬:问题中的yaml片段在系统重新启动后是有效的,仅仅运行'netplan应用‘是不够的。
https://askubuntu.com/questions/1174527
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