解析Bash脚本中的命令响应

Question

我需要一个bash脚本，它接受shell命令的输出并解析输出以提取状态。如果国家是:坏的，应该发送电子邮件。

~$ bucardo status
PID of Bucardo MCP: 2074
 Name     State       Last good               Time           Last I/D    Last bad                Time         
============================================+========+=======================+==============+===========+=======================+==============
 zenith | Good   | Jun 28, 2020 08:37:45 | 31h 13m 14s  | 1/1       | Jun 22, 2020 12:28:34 | 171h 22m 25s 
 zenith | Good   | Jun 23, 2020 19:12:42 | 140h 38m 17s | 4/4       | none                  |  

我还没能把Regex弄对

#!/usr/bin/env bash

bucardo status

while read line; do
  if [[ ! ${line} =~ ^[\+\| ]]; then
    if [[ ${line} =~ \|[[:space:]]*([[:alpha:]]+)[[:space:]]*\ ]]; then
      state="${BASH_REMATCH[1]}"
      echo "${state}"
    fi
  fi
done

Answer 1

if [[ ${line} =~ \|[[:space:]]*([[:alpha:]]+)[[:space:]]*\ ]]; then

应该是

if [[ ${line} =~ \|[[:space:]]*([[:alpha:]]+)[[:space:]]* ]]; then

(移除多余的\)。现在对我有用了。

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