gpgme-1.18无法编译

Question

我正在根据https://linuxfromscratch.org/blfs/view/systemd/postlfs/gpgme.html的说明从源代码编译gpgme-1.18

编译失败，出现以下错误：

Making all in python
make[2]: Entering directory '/home/brad_b82/gpgme-1.18.0/lang/python'
Making all in .
make[3]: Entering directory '/home/brad_b82/gpgme-1.18.0/lang/python'
set -e ; for PYTHON in /usr/bin/python3.10; do \
  CPP="gcc -E" \
  CFLAGS="-g -O2 -Wall -Wcast-align -Wshadow -Wstrict-prototypes -Wno-format-y2k -Wno-missing-field-initializers -Wno-sign-compare -Wno-format-zero-length -Wno-format-truncation -Wno-sizeof-pointer-div" \
  srcdir="." \
  top_builddir="../.." \
    $PYTHON setup.py build --verbose --build-base="$(basename "${PYTHON}")-gpg" ; \
done
running build
Using gpgme.h from ../../src/gpgme.h
Please use --libdir=LIBDIR option or set PKG_CONFIG_LIBDIR
Or set PKG_CONFIG_PATH
Could not find gpg-error-config.  Please install the libgpg-error development package.
make[3]: *** [Makefile:758: all-local] Error 1
make[3]: Leaving directory '/home/brad_b82/gpgme-1.18.0/lang/python'
make[2]: *** [Makefile:475: all-recursive] Error 1
make[2]: Leaving directory '/home/brad_b82/gpgme-1.18.0/lang/python'
make[1]: *** [Makefile:460: all-recursive] Error 1
make[1]: Leaving directory '/home/brad_b82/gpgme-1.18.0/lang'
make: *** [Makefile:538: all-recursive] Error 1

电脑在撒谎！在前面的配置过程中，脚本能够看到gpg-error-config。

checking for gpg-error-config... /usr/bin/gpg-error-config
checking for gpgrt-config... /usr/bin/gpgrt-config
configure: Use gpgrt-config with /usr/lib as gpg-error-config
checking for GPG Error - version >= 1.36... yes (1.46)
configure: Use gpgrt-config as libassuan-config

我可以确认它的路径位置：

brad_b82 [ ~ ]$ which gpg-error-config
/usr/bin/gpg-error-config
brad_b82 [ ~ ]$ 

gpg-error-config是一个符号链接：

brad_b82 [ ~ ]$ file /usr/bin/gpg-error-config 
/usr/bin/gpg-error-config: symbolic link to gpgrt-config
brad_b82 [ ~ ]$ 

当我运行gpg-error-config时，我得到以下信息：

brad_b82 [ ~ ]$ gpg-error-config
Please use --libdir=LIBDIR option or set PKG_CONFIG_LIBDIR
Or set PKG_CONFIG_PATH
brad_b82 [ ~ ]$

我不知所措，不知如何解决我的问题。任何帮助都是非常感谢的！

编辑1，关于BRUNSON

我确实验证了libgpg错误的位置，所以我也将相同的库复制到/usr/share/libgpg-error/文档告诉我这是默认位置。

Making all in python
make[2]: Entering directory '/home/brad_b82/gpgme-1.18.0/build1/build2/lang/python'
Making all in .
make[3]: Entering directory '/home/brad_b82/gpgme-1.18.0/build1/build2/lang/python'
ln -sf "../../../../src/data.h" .
ln -sf "../../conf/config.h" .
ln -sf "../../../../lang/python/src" gpg
touch copystamp
set -e ; for PYTHON in /usr/bin/python3.10; do \
  CPP="gcc -E" \
  CFLAGS="-g -O2 -Wall -Wcast-align -Wshadow -Wstrict-prototypes -Wno-format-y2k -Wno-missing-field-initializers -Wno-sign-compare -Wno-format-zero-length -Wno-format-truncation -Wno-sizeof-pointer-div" \
  srcdir="../../../../lang/python" \
  top_builddir="../.." \
    $PYTHON setup.py build --verbose --build-base="$(basename "${PYTHON}")-gpg" ; \
done
running build
Using gpgme.h from ../../src/gpgme.h
Please use --libdir=LIBDIR option or set PKG_CONFIG_LIBDIR
Or set PKG_CONFIG_PATH
Could not find gpg-error-config.  Please install the libgpg-error development package.
make[3]: *** [Makefile:758: all-local] Error 1
make[3]: Leaving directory '/home/brad_b82/gpgme-1.18.0/build1/build2/lang/python'
make[2]: *** [Makefile:475: all-recursive] Error 1
make[2]: Leaving directory '/home/brad_b82/gpgme-1.18.0/build1/build2/lang/python'
make[1]: *** [Makefile:460: all-recursive] Error 1
make[1]: Leaving directory '/home/brad_b82/gpgme-1.18.0/build1/build2/lang'
make: *** [Makefile:538: all-recursive] Error 1
brad_b82 [ ~/gpgme-1.18.0/build1/build2 ]$ ls /usr/lib/ | grep gpg
libgpg-error.so
libgpg-error.so.0
libgpg-error.so.0.33.1
brad_b82 [ ~/gpgme-1.18.0/build1/build2 ]$ ls /usr/share/libgpg-error/
errorref.txt  libgpg-error.so  libgpg-error.so.0  libgpg-error.so.0.33.1
brad_b82 [ ~/gpgme-1.18.0/build1/build2 ]$ 

我想指出的新事物。gpgme绑定的"cl“和"cpp”部分似乎编译得很好。直到它试图编译python绑定，它才会窒息。

我还试着阅读python部分中的每一行输出，我注意到一些奇怪的东西.Using gpgme.h来自../src/gpgme.h

不会有这样的路径，因为我所在的目录是: is ~/gpgme-1.18.0，扩展为/home/brad_b82/gpgme-1.18.0。

由于我没有足够的知识来解决这个问题，我决定简单地尝试：

cd ~
rm -Rf gpgme-1.18.0
tar -xvf gpgme-1.18.0.tar.bz2
cd gpgme-1.18.0
mkdir build1
cd build1
mkdir build2
cd build2
../../configure --prefix=/usr --libdir=/usr/lib --disable-gpg-test

我的思维过程是现在，.././src/gpgme.h实际上存在。但还是失败了。是的，我确实包含了--libdir=/usr/lib，只是为了试图覆盖基本内容，尽管在配置脚本中没有添加相同的路径。

Answer 1

我要回答这个问题然后结束它..。

linuxfromscratch最近向gpgme发布了解决这些问题的修补程序。

我不是一个程序员，但当我看到脚本试图从不存在的目录中提取时，我看起来至少是在正确的轨道上。

问题解决了，案子结束了。