如何正确地规避Makefile中的shell扩展语法$()?
.PHONY: test
test:
@if [ `find myDir -type f -not -name '*.openapi.yaml' | wc -l ` != 0 ]; then \
echo "All files must end with '.openapi.yaml'"; \
find myDir -type f -not -name '*.openapi.yaml'; \
exit 42; \
fi当我尝试修改它时,
@if [ $( find myDir -type f -not -name '*.openapi.yaml' | wc -l ) != 0 ]; then \我明白了,
/bin/sh: line 0: [: !=: unary operator expected如果我试图用$转义\$,我会得到同样的错误,
发布于 2021-03-27 01:57:40
您需要双$:
.PHONY: test test1 test2
test: test1 test2
test1:
@echo test1; if [ $(echo 0) == "0" ]; then echo true; else echo false; fi
test2:
@echo test2; if [ $(echo 0) == "1" ]; then echo true; else echo false; fi下面是一个例子:
$ make
test1
true
test2
falsehttps://unix.stackexchange.com/questions/641299
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