将目录内容移至静态命名子目录

Question

我的媒体目录结构如下：

~ $ tree baz
baz
├── Ajin [Season 1]
│   ├── Ajin Demi-Human - 01 - A Topic That Has Nothing to Do with Us.mkv
│   ├── Ajin Demi-Human - 02 - Why Is This Happening to Me I Didn`t Do Anything Wrong!.mkv
...snip...
├── Btooom!
│   ├── Btooom! - 01 - Start.mkv
│   ├── Btooom! - 02 - The Bloodstained High School Girl.mkv
...snip...
└── Claymore [Dual Audio]
    ├── checksums.md5
    ├── Claymore - 01 - Great Sword.mkv
    ├── Claymore - 02 - The Black Card.mkv
    ├── Claymore - 03 - The Darkness in Paradise.mkv
...snip...

3 directories, 53 files

我需要横越baz目录，并为每个子目录创建一个名为“第01季”的子目录，并将所有文件(和任何目录)放入新创建的子目录“第01季”。

例如，上述情况将成为：

baz
├── Ajin [Season 1]
│   ├── Season 01
│       ├── Ajin Demi-Human - 01 - A Topic That Has Nothing to Do with Us.mkv
│       ├── Ajin Demi-Human - 02 - Why Is This Happening to Me I Didn`t Do Anything Wrong!.mkv
...snip...
etc

我试图使用find来完成这个任务，但是我想不出如何构造-exec命令来创建“第01季”目录，并将目录的内容移到新的目录中。

谢谢

Answer 1

你只需要一个简单的循环。

cur=$(pwd)
for i in baz/*
do
    cd "$i"
    mkdir season1
    mv *.mkv season1
    cd "$cur"
done

Answer 2

使用bash：

shopt -s dotglob
for i in baz/*/*; do
  mkdir -p "${i%/*}/Season 01"
  mv "$i" "${i%/*}/Season 01"
done

首先，让dotglob也能匹配隐藏的文件。然后循环遍历baz子目录中的文件和

• 如果Season 01目录还不存在，就创建它。参数展开${i%/*}移除文件名并保留父目录(例如，baz/Ajin [Season 1])。
• 将当前文件"$i"移到季节目录中。