命令的输出与其符号链接的输出不匹配

Question

我在我的覆盆子皮上使用RASPBIAN。我发现，命令“意外”是命令"wahtis“的一个符号链接。但是，当使用相同的参数时，这些命令的输出不匹配：

$ whatis delete
delete: nothing appropriate.

但

$ apropos delete
argz_delete (3)      - functions to handle an argz list
delete_module (2)    - unload a kernel module
dphys-swapfile (8)   - set up, mount/unmount, and delete an swap file
git-branch (1)       - List, create, or delete branches
git-replace (1)      - Create, list, delete refs to replace objects
git-symbolic-ref (1) - Read, modify and delete symbolic refs
git-tag (1)          - Create, list, delete or verify a tag object signed 
***output is truncated to save space....***

很明显，这是一个象征性的联系。

pi@raspberry:~ $ which apropos
/usr/bin/apropos
pi@raspberry:~ $ ls -l /usr/bin/apropos
lrwxrwxrwx 1 root root 6 Aug 24  2017 /usr/bin/apropos -> whatis

怎么会发生这种事？

Answer 1

正在运行的可执行文件将知道完整的调用命令行，并可以根据调用的名称修改其行为。对于apropos/whatis的特定实例，您可以看到在源代码中 (链接的最近版本的第895行)，首先要确定命令是否以名称apropos调用：

int main (int argc, char *argv[])
{
#ifdef HAVE_ICONV
    char *locale_charset;
#endif
    int status = OK;

    program_name = base_name (argv[0]);
    if (STREQ (program_name, APROPOS_NAME)) {
        am_apropos = 1;
        argp_program_version = "apropos " PACKAGE_VERSION;
    } else {

在处理过程中，大约有十几个地方检查am_apropos标志，根据是否设置了它，它们的行为有所不同。