如何同样使用shell脚本获取季度信息,如最后、当前、下一季度
发布于 2018-04-03 11:30:48
这将使用bash完成它:
declare -i m=$(date +%m)
declare -i cq=($m-1)/3+1
declare -i cy=$(date +%Y)
declare -i py=$cy; [ $m -lt 4 ] && py=$cy-1
declare -i pq=$cq-1; [ $pq -eq 0 ] && pq=4
declare -i ny=$cy; [ $m -gt 9 ] && ny=$cy+1
declare -i nq=$cq+1; [ $nq -gt 4 ] && nq=1
echo ${py}q${pq},${cy}q${cq},${ny}q${nq}行政长官: 2018q1,2018q2,2018q3
发布于 2018-04-03 12:10:57
month=$(date +%m)
quarter=$(( (2 + 10#$month) / 3 ))演示
for m in {1..12}; do
read y m < <(date -d "2018-$m-1" "+%Y %m")
printf "%s-%s is in q%d\n" "$y" "$m" "$(( (2 + 10#$m) / 3))"
done2018-01 is in q1
2018-02 is in q1
2018-03 is in q1
2018-04 is in q2
2018-05 is in q2
2018-06 is in q2
2018-07 is in q3
2018-08 is in q3
2018-09 is in q3
2018-10 is in q4
2018-11 is in q4
2018-12 is in q4我们需要在算术表达式中使用10#$month,因为否则08和09会抛出“无效八进制数”错误。
https://unix.stackexchange.com/questions/435249
复制相似问题