数字的印刷因素和主要因素

Question

我是个46岁的年轻新手，为了好玩和冒险学习编程。我是在业余时间做这个的。一些非常好的先生在堆叠溢出派我来这里。我希望有人能检查我的代码，找出我的风格和薄弱环节的错误，这样我就可以在上面工作了。

prime_numbers = [2,   3,   5,   7,  11,  13,  17,  19,  23,  29,  31,  37,  41,  43,  47,  53,  59,  61,  67,  71,  73,  79,  83,  89,  97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 947, 953, 967, 971, 977, 983, 991, 997 ]
list_of_factors = []
list_of_Prime_factors = []


def look4factors(number):
    global list_of_factors
    for index in range (2, 1 + number/2):
        if number % index == 0:
            list_of_factors.append (index)

#-------------------------------------------------------------------                   

def find_prime_factors(number):
    global list_of_factors
    global prime_numbers
    global list_of_Prime_factors
    quotient = number
    while (quotient > 1):
        for index in range(0,len(prime_numbers)):
            if (quotient % prime_numbers[index] == 0 ):
                list_of_Prime_factors.append(prime_numbers[index])
                quotient = quotient / prime_numbers[index]

#------------------------------------------------------------------                      

def print_all_factors(number):
        global list_of_factors
        print "\n\nThe Factors for {} are,".format(number),
        for index in range (0, len(list_of_factors)):
            print "{}".format(list_of_factors[index]), 
            print "",

#-------------------------------------------------------------------

def print_all_prime_factors(number):
        global list_of_Prime_factors
        find_prime_factors(number)
        list_of_Prime_factors.sort()
        print "\n\nThe Prime Factorization for {} would be = ".format(number),
        for index in range (0, len(list_of_Prime_factors)):
            print "{}".format(list_of_Prime_factors[index]), 
            if (index + 1 == len(list_of_Prime_factors)):
                pass
            else:
                print "X",

#-------------------------------------------------------------------        

def main():
    str_product = raw_input("Please enter a number to get its factors ")
    int_product = int(str_product)
    look4factors(int_product)
    if len(list_of_factors)== 0:
        print "It's a Prime Number."
    else:
        print_all_factors(int_product)
        print_all_prime_factors(int_product)



if __name__ == "__main__":
    main()

Answer 1