无法在读取文件时替换字符串

Question

final.txt看起来像：

build/create_changes.sh
build/create_changes.sh-meta.xml
src/aura/camping/camping.design
src/aura/camping/camping.design-meta.xml

代码是这样的：

if [ -e final.txt ]
then
    ARRAY=()
    while read CFILE
    do
        echo Analyzing file `basename $CFILE`
        case "$CFILE"
            in
            *.design) TYPENAME="AuraDefinitionBundle";;
            *) TYPENAME="UNKNOWN";;
        esac

        if [ "$TYPENAME" == "AuraDefinitionBundle" ]
        then
            if [ $(contains "${ARRAY[@]}" $(basename -- "$(dirname -- "$CFILE")")) != "y" ]
            then
                echo baseFile from new method cFile $CFILE
                CFILENAME="$CFILE"

                replace="src/aura/"$(basename -- "$(dirname -- "$CFILE")")
                echo checkChanges "${CFILENAME/$CFILENAME/"$replace"}"
                CFILE="${CFILENAME/$CFILENAME/"$replace"}"
                echo baseFile from after change method cFile $CFILE
            else
                continue
            fi
        fi
    done < final.txt
else
    echo Change file not found!

我可以在回声窗口看到：

 [exec] baseFile from new method cFile src/aura/camping/camping.design
 [exec] checkChanges src/aura/camping
 [exec] baseFile from after change method cFile src/aura/camping

但是文件没有改变，我甚至添加了sed命令，但是输出没有改变：

if [ $(contains "${ARRAY[@]}" $(basename -- "$(dirname -- "$CFILE")")) != "y" ]
then
    CFILENAME="$CFILE"
    ARRAY+=($(basename -- "$(dirname -- "$CFILE")"))
    replace="src/aura/"$(basename -- "$(dirname -- "$CFILE")")
    #CFILE="${CFILENAME/$CFILENAME/"$replace"}"
    sed -i 's/$CFILENAME/$replace/' final.txt
else
    continue
fi

Expected输入

build/create_changes.sh
build/create_changes.sh-meta.xml
src/aura/camping/camping.design
src/aura/camping/camping.design-meta.xml

Expected输出

build/create_changes.sh
build/create_changes.sh-meta.xml
src/aura/camping
src/aura/camping/camping.design-meta.xml

Answer 1

我不确定我能不能理解你的逻辑，但是这个

awk '/\.design$/ {sub("/[^/]*$", "")} 1 ' file
build/create_changes.sh
build/create_changes.sh-meta.xml
src/aura/camping
src/aura/camping/camping.design-meta.xml

会产生期望的输出..。

Answer 2

如果您只想删除以.design结尾的所有路径名的basename：

sed 's#/[^/]*\.design$##' final.txt

要执行就地编辑，请在上面的表达式中使用sed -i ( -i标志的工作方式略有不同，但这将适用于GNU sed )。

正则表达式/[^/]*\.design$匹配一个/，后面跟着任意数量的非/字符，以及行尾的文字字符串.design。