我正试图通过使用x杯来降低显示器的对比度。这是我的作品。
Screen 0: minimum 8 x 8, current 3840 x 1200, maximum 32767 x 32767
DVI-D-0 connected primary 1920x1080+0+0 (normal left inverted right x axis y axis) 527mm x 296mm
1920x1080 60.00*+
1680x1050 59.95
1600x900 60.00
1440x900 59.89
1280x1024 75.02 60.02
1280x720 60.00
1024x768 75.03 60.00
800x600 75.00 60.32
640x480 75.00 59.94
HDMI-0 connected 1920x1200+1920+0 (normal left inverted right x axis y axis) 518mm x 324mm
1920x1200 59.95*+
1920x1080 60.00
1680x1050 59.95
1600x1200 60.00
1280x1024 60.02
1280x960 60.00
1024x768 60.00
800x600 60.32
640x480 59.94
DP-0 disconnected (normal left inverted right x axis y axis)
DP-1 disconnected (normal left inverted right x axis y axis)
DP-2 disconnected (normal left inverted right x axis y axis)
DP-3 disconnected (normal left inverted right x axis y axis)
DP-4 disconnected (normal left inverted right x axis y axis)
DP-5 disconnected (normal left inverted right x axis y axis)我现在可以用这个命令按比例改变两个显示器的对比-
xcalib -co 80 -a #reduces contrast by 80 percent.如何指定监视器名称?
xcalib -co -80 -d DVI-D-0抛出错误-无法打开显示
发布于 2018-09-05 21:39:31
试错xcalib的S -screen参数根据您的xrandr输出获取监视器的零索引编号,也就是说,在您的示例中,xcalib -s 0 (默认)将控制DVI-D-0,xcalib -s 1将控制HDMI-0。
https://unix.stackexchange.com/questions/418206
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