计算停车费

Question

下面是描述：

请编写一个管理停车费的Java程序。每小时3美元。

1. 发票必须包含: ID、金额和小计。
2. 当天的最高收费为30美元，并提供一张5美元的优惠券.
3. 停车位总数必须超过0。如果输入的汽车小于0时，将显示错误消息。
4. 总停车时间必须>0小时和<24小时。如果输入的时数不正确，则将显示错误消息。

这是输出的一个例子：

Please enter today's total parked cars: -3

The number you entered is less than 0, please re-enter: 0

The number you entered is less than 0, please re-enter: 8

Please enter your 1st car's parking hours: -1

The parking hours entered is incorrect, please re-enter: 25

The parking hours entered is incorrect, please re-enter: 30

The parking hours entered is incorrect, please re-enter: 24

Please enter your 2nd car's parking hours: 2

Please enter your 3rd car's parking hours: 5

Please enter your 4th car's parking hours: 9

Please enter your 5th car's parking hours: 4

Please enter your 6th car's parking hours: 3

----today's parking invoice----

ID.   Amount      Subtotal

1 _______30 _______ 30   *coupon

2 _______6 _______  36      

3 _______ 12_______ 48

4 _______ 3 _______   51  

5 _______30  _______  81    *coupon         

Today's total:$81

这是我的代码：

import java.util.Scanner;

public class Tryagainparking {
    public static void main(String[] args) 
    {
        Scanner keyboard=new Scanner(System.in);
        System.out.print("Total parked cars:");
        int NUMBER_OF_CARS = keyboard.nextInt();
        
        while (NUMBER_OF_CARS<=0)
        {
            System.out.print("Cars has to >0，please re-entere：");
            int NUMBER_OF_CARS2 = keyboard.nextInt();
            if (NUMBER_OF_CARS2>0)
                break;
        }
        
        double hoursParked=0;
        double EveryAmount=0;
        int totalincome=0;
        int counter=1;
        
         
        for (int count=1;count<=NUMBER_OF_CARS;count++)
        {
             System.out.printf("this is the %d data:",count);
             hoursParked=keyboard.nextInt();
                while(hoursParked<=0)
                { 
                    System.out.printf("parking hour is incorrect, please re-eneter");
                    int hoursParked2=keyboard.nextInt();
                }
                while(hoursParked>=24)
                { 
                    System.out.printf("parking hour is incorrect, please re-eneter");
                    int hoursParked2=keyboard.nextInt();
                }
            EveryAmount=(hoursParked)*30;
                if (EveryAmount>=300)
                    EveryAmount=300;
            totalincome+=EveryAmount;
        
            
        }
        System.out.print("----invoice------\n");
        System.out.print("ID     Amount     Subtotal");
        
        System.out.printf("%s",counter);
    
        
        
    }
}

Answer 1

这个测试看上去是错误的：

while(hoursParked<=0) { System.out.printf("parking hour is incorrect, please re-eneter"); int hoursParked2=keyboard.nextInt(); } while(hoursParked>=24) { System.out.printf("parking hour is incorrect, please re-eneter"); int hoursParked2=keyboard.nextInt(); }

在第二个循环中，我们可以输入一个负值，这将被接受。

我们希望替换我们之前读到的值，而不是扔掉它(当我们读取汽车数量时，我们似乎遇到了同样的问题)。

我们需要一个循环来重复，直到满足所有条件：

                while (hoursParked<=0 || hoursParked>=24)
                { 
                    System.out.printf("parking hour is incorrect, please re-enter");
                    hoursParked = keyboard.nextInt();
                }