如何将Solidity函数返回的struct数组类型转换为Go类型？

Question

坚固版0.6.10

struct LogisticsData {
        address cargo;
        address orgin;
        address destination;
        string memo;
        uint createdAt;
        uint queryCount;
}

function getLogisticsInfo(address cargo) public returns(LogisticsData[] memory _cargoLogisticsData) {
    _cargoLogisticsData = new LogisticsData[](3);
   // do something
}

由abigen生成的Go代码

type LogisticsLogisticsData struct {
    Cargo       common.Address
    Orgin       common.Address
    Destination common.Address
    Memo        string
    CreatedAt   *big.Int
    QueryCount  *big.Int
}

我尝试了以下代码，但它返回了一个错误。

_, receipt, _ := instance.GetLogisticsInfo(client.GetTransactOpts(), common.HexToAddress(address))
parsedAbi, _ := abi.JSON(strings.NewReader(logistics.LogisticsABI))
temp := make([]logistics.LogisticsLogisticsData, 10)
err = parsedAbi.Unpack(&temp, "getLogisticsInfo", []byte(receipt.Output))
fmt.Println(err) // abi: improperly formatted output: xxx

我希望将返回数据转换为LogisticsLogisticsData结构。该怎么做呢？

Answer 1

需要将十六进制转换为二进制

bytesOutput, _ := hex.DecodeString(receipt.Output[2:])
err = parsedAbi.Unpack(&temp, "getLogisticsInfo", bytesOutput)