我不能把这两种价值观一分为二。

Question

  function calculate(
   uint index
       )public view returns(uint, uint, bool){
   uint avh1;
   uint avh2;
   uint avh3;
   uint avl1;
   uint avl2;
   uint avl3;
  
   uint allowbuy;
   uint allowsell;
           //function add(uint256 a, uint256 b) internal pure returns (uint256) {
        //   return a + b;
           priceHistory memory coinToReturn = stableCoins[index];
           
           avh1 = coinToReturn.highestPricethismonth.add (coinToReturn.highestPrice2MonthsAgo);
           avh2 = coinToReturn.highestPrice3MonthsAgo.add (coinToReturn.highestPrice4MonthsAgo);
           avh3 = avh1.add (avh2); avh3/4= allowsell;
           avl1 = coinToReturn.lowestPricethismonth.add (coinToReturn.lowestPrice2MonthsAgo);
           avl2 = coinToReturn.lowestPrice3MonthsAgo.add (coinToReturn.lowestPrice4MonthsAgo);
           avl3 = avl1.add (avl2); avl3.div  (4)  = allowbuy;
           
           
          return (allowbuy);
          return (allowsell);
          return (success);
        
        }

在我最后被分割的行中，无论我使用什么方法来划分，我都会得到同样的错误消息，“表达式必须是一个1值”。

Answer 1

这些都是无效的稳固代码。

avh3/4= allowsell;

...

avl3.div  (4)  = allowbuy;

若要将结果分配给变量，您必须左、右交换。

allowsell = avh3/4;

...

allowbuy = avl3.div(4);