uint256[]数组格式

Question

我目前正试图在以太上启用zk的验证。我使用的zk证明是一个uint2568数组。我设法在本地验证它，但是如果我想通过Etherscan合同接口将它提交给Rinkeby的话。当我试图将值写成数组时，我会得到一个typeerror。

我想知道是否有人知道使用MEW/Etherscan或其他平台将数组(uint2568)写入合同时的格式是否正确？

合同

https://rinkeby.etherscan.io/address/0x56804F39a898b2607ecd41A7F6a4D482DC15073f#writeContract

值

deployRenter: 0.6

0x3864db492ea1817cd722e69210857480075a08da7d5aab3da4c60d4da1a03125：_ppc

0xdf79e84fa75d57fc84d4dcdee39030f33714c4c1beeff804e26af8a1314e592e：_r

0x781f0568991dfac047eaf9ebe83df3e24254bf1d7ccfcac49c20f187be19593b：_s

_v: 27

Verify_deployRenterproof：'11014804280498173996371870034282977682206158250531495349377289989445413365492'，'21227707827012713913025612553955593860819922575810543781723818087545239424785'，'20455701651325141130707960947541191569094470759307876535045331233510970382977'，'20878365366855099273541058485942850396375994988992146685194295423210057056533'，'4789227134106595071719519609365832853516546056916330161072411497180681132151'，'12057322530346973393171898575858898867552551582146891559350101405991713199093'，'6397540020422338085233907082172467475349404015162612289997239902254115476791'，'14486654477843838294702863102857924644412904839305621820045087144397542093670‘

genParam：“60000000000000020”

Answer 1

混合时uint2568输入的格式如下：

"0x1dad21c7e2e06c49150029885aa66a5b3838ecb285eac0c99992b86eec69b9f7"，"0x06d8cb9bc99d787b486478b78450871782a36b76edc198c3477e893043d99cc5"，"0x24f30366745359bf022bac5f75bcef4bff819868c4a4d5eec66e40b8c5399c7d"，"0x200f7f266e3e8ebf7ca70a884006c7d1705a36a19e1078a0fb738f8fe16b7af1"，"0x226dee3fe96cb68dfea5f4e29a136c194e7bf0a84008f7f5a3702100c28b369a"，"0x0fba3eef067319766d5a1ceb67a58548f12cd6868482d8f62b1d060cd783c3de"，"0x2deae3c6bf665d84cbf8795c458aa156b41104c74b2e69a07856bcfab3bf9434"，"0x0344b184bd9cd023d2db2f22d675126466e97a5677c90cbf37a926be2ed22486“

不能有空格，十六进制格式是uint256的有效表示形式。

Answer 2

在以太扫描中，当我在没有引号的情况下传递十六进制值时，它对我有效。所以

_inputNumbers (uint256[6]) of [200, 300, 500, 1500, 2500, 5000]

将会是

[0xC8,0x12C,0x1F4,0x5DC,0x9C4,0x1388]