-server -Xmx100g -Xms100g -XX:MaxMetaspaceSize=1G -Xss512k
-XX:+UnlockExperimentalVMOptions -XX:+UseZGC -XX:MaxGCPauseMillis=30
-XX:ConcGCThreads=4 -XX:ParallelGCThreads=12
-XX:+DisableExplicitGC -XX:LargePageSizeInBytes=128m total used free shared buffers cached
Mem: 251 250 1 100 0 138
-/+ buffers/cache: 112 139
Swap: 7 0 7 PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND
240731 xxx 20 0 17.0t 302g 297g S 6.6 119.9 256:35.43 java./jhsdb jmap --heap --pid 240731
Attaching to process ID 240731, please wait...
Debugger attached successfully.
Server compiler detected.
JVM version is 11.0.2+9
using thread-local object allocation.
ZGC with 12 thread(s)
Heap Configuration:
MinHeapFreeRatio = 40
MaxHeapFreeRatio = 70
MaxHeapSize = 107374182400 (102400.0MB)
NewSize = 1363144 (1.2999954223632812MB)
MaxNewSize = 17592186044415 MB
OldSize = 5452592 (5.1999969482421875MB)
NewRatio = 2
SurvivorRatio = 8
MetaspaceSize = 21807104 (20.796875MB)
CompressedClassSpaceSize = 1073741824 (1024.0MB)
MaxMetaspaceSize = 1073741824 (1024.0MB)
G1HeapRegionSize = 0 (0.0MB)
Heap Usage:
ZHeap used 82988M, capacity 1024M, max capacity 27112449862M对于最大容量还有其他的VM选项吗?ZGC堆是如何工作的?
发布于 2020-04-28 00:20:37
既然这个问题不时被问到,而我已经厌倦了解释,那就让我试着把它放在这里,这样人们就可以简单地搜索,得到答案,重新快乐(即使在很短的一段时间内,它仍然是值得的!)
ZGC的RSS过度报告是由于ZGC用于操作内存页的技术,即多映射。而且,由于ZGC本质上是Zing C4收集器(由Azul Systems)的另一个实现,Zing也有同样的“过度报告”RSS问题。
查看以下代码:
x86.cpp#l160
void ZPhysicalMemoryBacking::map(ZPhysicalMemory pmem, uintptr_t offset) const {
if (ZUnmapBadViews) {
// Only map the good view, for debugging only
map_view(pmem, ZAddress::good(offset), AlwaysPreTouch);
} else {
// Map all views
map_view(pmem, ZAddress::marked0(offset), AlwaysPreTouch);
map_view(pmem, ZAddress::marked1(offset), AlwaysPreTouch);
map_view(pmem, ZAddress::remapped(offset), AlwaysPreTouch);
}
}这是:
void ZPhysicalMemoryBacking::map_view(ZPhysicalMemory pmem, uintptr_t addr, bool pretouch) const {
const size_t nsegments = pmem.nsegments();
// Map segments
for (size_t i = 0; i < nsegments; i++) {
const ZPhysicalMemorySegment segment = pmem.segment(i);
const size_t size = segment.size();
const void* const res = mmap((void*)addr, size, PROT_READ|PROT_WRITE, MAP_FIXED|MAP_SHARED, _file.fd(), segment.start());
if (res == MAP_FAILED) {
ZErrno err;
map_failed(err);
}
// Advise on use of transparent huge pages before touching it
if (ZLargePages::is_transparent()) {
advise_view(addr, size);
}
// NUMA interleave memory before touching it
ZNUMA::memory_interleave(addr, size);
if (pretouch) {
pretouch_view(addr, size);
}
addr += size;
}
}绘制所有视图:
这意味着,对于相同的地址,ZGC将将其映射到3个不同的视图: marked0、marked1和remapped。这3个视图反映在虚拟内存地址中。这意味着,3个不同的虚拟内存地址将映射到相同的底层物理内存,因此对于每个物理内存页,有3个虚拟页映射到它。
如果ZGC成长为一代GC (年轻一代和老一代,而不是现在的ZGC一代),我们可以预期这个数字也会增加到xmx堆大小的6倍。
这就是为什么Azul Zing和Oracle所使用的多映射将人们置于"top“命令下的恐慌状态。但是请注意,只有虚拟内存空间才会被报告,所以除非您的系统工具遇到了这个令人困惑的部分,否则您没有理由拨打911。
https://stackoverflow.com/questions/57899020
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