首页
学习
活动
专区
圈层
工具
发布

SUBSTR组
EN

Stack Overflow用户
提问于 2019-08-21 00:52:09
回答 2查看 80关注 0票数 0

有人能解释一下为什么下面的代码没有错误吗?

代码语言:javascript
复制
SELECT t1.column1,
       t1.column2,
       t1.column3,
       ctot as Cost,
       (ctot * t1.qty) as FinalCost
FROM Table1 t1

LEFT JOIN (SELECT column1,
                  column2,
                  column3,
                  column4,
             MAX(DateCol),
             AVG(CostCol) KEEP(DENSE_RANK LAST ORDER BY t2.DateCol) as ctot
FROM Table2 t2
GROUP BY column1, column2, SUBSTR(column3, 1, 5), column4) t2
     ON t2.column1 = t1.column1
     AND t2.column2 = t1.column2
     AND t2.column4 = t1.column4
     AND SUBSTR(t1.column3, 1, 5) = SUBSTR(t2.column3, 1, 5)
     WHERE t1.ID1 = '500'
     AND t1.ID2 != '50'

而这段代码将产生错误ORA-00979: not a GROUP BY expression

代码语言:javascript
复制
SELECT t1.column1,
       t1.column2,
       t1.column3,
       ctot as Cost,
       (ctot * t1.qty) as FinalCost
FROM Table1 t1

LEFT JOIN Table2 t2
    ON t1.column1 = t2.column1
   AND t1.column2 = t2.column2

LEFT JOIN (SELECT IdCol as points, column3 FROM Table3) t3
    ON t2.column3 = t3.column3

LEFT JOIN (SELECT column1,
                  column3,
             MAX(DateCol),
             AVG(CostCol) KEEP(DENSE_RANK LAST ORDER BY t4.DateCol) as ctot
FROM Table4 t4
GROUP BY column1, SUBSTR(column3, 1, 5)) t4
    ON t4.column1 = points
   AND SUBSTR(t4.column3, 1, 5) = SUBSTR(t1.column3, 1, 5)
 WHERE t1.ID1 = '500'
   AND t1.ID2 != '50'

我的编辑器在最后一个join语句中突出显示column3是导致错误的原因,并将SUBSTR(column3, 1, 5)替换为GROUP BY语句中的column3修复了此错误。但是为什么在第二个示例中抛出错误,而不是在第一个示例中抛出错误?它与多个join语句有关吗?

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2019-08-22 12:35:57

您在主选择中使用LEFT JOIN,这意味着甲骨文正在使用SQL92。因此,您必须在GROUP BY clausule exat的SELECT投影部分使用。

埃伊岛在子选择中使用此方法:

代码语言:javascript
复制
SELECT column1,
    column2,
    SUBSTR(column3, 1, 5) as column3, -- column3 after substr()
    column4,
    MAX(DateCol),
    AVG(CostCol) KEEP(DENSE_RANK LAST ORDER BY t2.DateCol) AS ctot
FROM Table2 t2
GROUP BY column1, column2, SUBSTR(column3, 1, 5), column4
票数 1
EN

Stack Overflow用户

发布于 2019-08-21 01:17:51

在声明结束时额外的) ..。

应该只是

代码语言:javascript
复制
SELECT
  t1.column1,
  t1.column2,
  t1.column3,
  ctot AS Cost,
  (ctot * t1.qty) AS FinalCost
FROM Table1 t1

LEFT JOIN (SELECT
  column1,
  column2,
  column3,
  column4,
  MAX(DateCol),
  AVG(CostCol) KEEP (DENSE_RANK LAST ORDER BY t2.DateCol) AS ctot
FROM Table2 t2
GROUP BY column1,
         column2,
         SUBSTR(column3, 1, 5),
         column4) t2

  ON t2.column1 = t1.column1
  AND t2.column2 = t1.column2
  AND t2.column4 = t1.column4
  AND SUBSTR(t1.column3, 1, 5) = SUBSTR(t2.column3, 1, 5)
WHERE t1.ID1 = '500'
AND t1.ID2 != '50'
票数 -1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/57583132

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档