变量“azurerm_sql_server.sql_server”的资源“azurerm_sql_server.sql_server.name”找不到

Question

我用var.sql_server_enable创建了带有启用/禁用选项的sql，但在输出方面遇到了问题。如果var.sql_server_enable为0，则azurerm_sql_server.sql_server.name将为null，我将得到以下错误。

resource "azurerm_sql_server" "sql_server" {
  count                        = "${var.sql_server_enable ? 1 : 0}"
  name                         = "${var.sql_server_name}"
  resource_group_name          = "${var.sql_server_resource_group_name}"
  location                     = "${var.sql_server_location}"
  version                      = "${var.sql_server_version}"
  administrator_login          = "${var.sql_server_admin_user}"
  administrator_login_password = "${var.sql_server_admin_pass}"
}

output "sql_server_name_output" {
  value = "${var.sql_server_enable == "1" ? azurerm_sql_server.sql_server.name : var.null }"
}

Error: Error running plan: 1 error occurred:
        * module.hello.module.azure_sql_server_hello_staging.output.sql_server_name_output: Resource 'azurerm_sql_server.sql_server' not found for variable 'azurerm_sql_server.sql_server.name'

Answer 1

谢谢您的回答，但是在另一个模块上使用了sql_server_name_output变量。它需要string值。然后我使用var.null而不是null。在我听从你的建议后，我在下面又犯了一个错误。你还有其他建议吗？

Error: Inconsistent conditional result types

  on ../modules/azure_sql_server/output.tf line 9, in output "sql_server_name_output":
   9:   value = "${var.sql_server_enable ? azurerm_sql_server.sql_server[*].name : var.null }"
    |----------------
    | azurerm_sql_server.sql_server is tuple with 1 element
    | var.null is "null"
    | var.sql_server_enable is true

另一个需要azurerm_sql_server.sql_server的资源位于下面。

resource "azurerm_sql_firewall_rule" "sql_firewall_rule" {
  count               = "${var.sql_fw_enable == "1" ? 1 : 0}"
  name                = "${var.sql_fw_rule_name}"
  resource_group_name = "${var.sql_fw_rule_resource_group_name}"
  server_name         = "${azurerm_sql_server.sql_server}"
  start_ip_address    = "${var.sql_fw_rule_start_ip}"
  end_ip_address      = "${var.sql_fw_rule_end_ip}"
}