UIColor扩展

Question

我在objective中扩展了UIColor类，头文件如下所示：

@interface UIColor (ColorDecision)
+ (UIColor*) directOrLegacyWithColor;
+ (UIColor*) changeColor;
@end

执行情况：

#import "UIColor+ColorDecision.h"

@implementation UIColor (ColorDecision)
 + (UIColor *)directOrLegacyWithColor {
     UIColor *color;
     UIColor *returenedColor = self.changeColor;
     color = LoginsManager.getSharedInstance.isDirect ? returenedColor : [UIColor self];
     return color;
}

 + (UIColor *)changeColor{
     UIColor *newColor;
     if (self == Color_C7) newColor = Color_Direct;

     return newColor;
}
@end

我收到编译器在下面一行的警告：“不兼容指针类型”将“UIColor*”从“类”分配给“*”。

color = LoginsManager.getSharedInstance.isDirect ? returenedColor : [UIColor self];

我知道问题与指针有多大的关系，但我不知道该怎么做。

编辑

由于manishharma93注释，我现在解决了第一个问题，当我想要使用指定的方法时，这些方法似乎是不可见的。

我在全局头文件中定义了颜色，如下所示：

#define Color_C7           [SharedUtility colorWithHexString:@"FF6A00"] // orange
#define Color_Direct      [Utility colorWithHexString:@"313d53"] // Color for direct

这是Utility中'colorWithHexString‘函数的实现：

+(UIColor *)colorWithHexString:(NSString *)hexString {
NSString *colorString = [[hexString stringByReplacingOccurrencesOfString: @"#" withString: @""] uppercaseString];
CGFloat alpha, red, blue, green;
switch ([colorString length]) {
    case 3: // #RGB
        alpha = 1.0f;
        red   = [SharedUtility colorComponentFrom: colorString start: 0 length: 1];
        green = [SharedUtility colorComponentFrom: colorString start: 1 length: 1];
        blue  = [SharedUtility colorComponentFrom: colorString start: 2 length: 1];
        break;
    case 4: // #ARGB
        alpha = [SharedUtility colorComponentFrom: colorString start: 0 length: 1];
        red   = [SharedUtility colorComponentFrom: colorString start: 1 length: 1];
        green = [SharedUtility colorComponentFrom: colorString start: 2 length: 1];
        blue  = [SharedUtility colorComponentFrom: colorString start: 3 length: 1];
        break;
    case 6: // #RRGGBB
        alpha = 1.0f;
        red   = [SharedUtility colorComponentFrom: colorString start: 0 length: 2];
        green = [SharedUtility colorComponentFrom: colorString start: 2 length: 2];
        blue  = [SharedUtility colorComponentFrom: colorString start: 4 length: 2];
        break;
    case 8: // #AARRGGBB
        alpha = [SharedUtility colorComponentFrom: colorString start: 0 length: 2];
        red   = [SharedUtility colorComponentFrom: colorString start: 2 length: 2];
        green = [SharedUtility colorComponentFrom: colorString start: 4 length: 2];
        blue  = [SharedUtility colorComponentFrom: colorString start: 6 length: 2];
        break;
    default:
        LOG(@"WARNING: tried to set color from string: %@ BUT string should be  a hex value of the form #RBG, #ARGB, #RRGGBB, or #AARRGGBB ", hexString);
        return nil;
        break;
}
return [UIColor colorWithRed: red green: green blue: blue alpha: alpha];
}

现在，当我想使用我的扩展函数时，例如: self.background = Color_C7。directOrLegacyWithColor 'directOrLegacyWithColor‘函数不可见

Answer 1

在您的方法中，将"self“改为"UIColor self”。

+ (UIColor *)directOrLegacyWithColor {
     UIColor *color;
     UIColor *returenedColor = self.changeColor;
     color = LoginsManager.getSharedInstance.isDirect ? returenedColor : [UIColor self];
     return color;
}