如何在列表中分隔逗号分隔的值，使其成为列表的单个值

Question

我在python中获取列表中的一些开关命令输出，我可以在list中得到结果，但是这个列表包含两个元素，甚至那些元素都是逗号分隔的，我希望将这些逗号分隔的值作为list的单个元素。

我使用netmiko模块，在这里我使用python在list中取出一些命令输出。

                for k in range(len(cli_commands)):
                    net_connect.send_command(cli_commands[k])
                    vall=net_connect.send_command(cli_commands[k])
                    myList1.append(vall)
              ```print(myList)

Actual result is:

['Cisco IOS Software, C2960S Software (C2960S-UNIVERSALK9-M), Version 15.0(2)SE11, RELEASE SOFTWARE (fc3)', 'NAME: "1", DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L  , VID: V02  , SN: FOC1452X5C5\n\n']


Expectation:

['Cisco IOS Software', 'C2960S Software (C2960S-UNIVERSALK9-M)', 'Version 15.0(2)SE11', 'RELEASE SOFTWARE (fc3)', 'NAME: "1"', 'DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L'  ,' VID: V02'  , 'SN: FOC1452X5C5\n\n']

or
['Cisco IOS Software','C2960S Software (C2960S-UNIVERSALK9-M)',Version 15.0(2)SE11','DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L','SN: FOC1452X5C5\n\n']

Answer 1

您必须对每个字符串进行.split(',')，以获得嵌套列表，然后使其变得简单明了。.split()的使用会在每个sub_string的开头和结尾删除额外的空格。

the_list = ['Cisco IOS Software, C2960S Software (C2960S-UNIVERSALK9-M), Version 15.0(2)SE11, RELEASE SOFTWARE (fc3)', 'NAME: "1", DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L  , VID: V02  , SN: FOC1452X5C5\n\n']

the_list = [map(lambda x: x.strip(), item.split(',')) for item in the_list]
new_list = [item for sub_list in the_list for item in sub_list]

第一行将the_list中的每个字符串转换为映射生成器，在被','字符除以后将.strip() (修整空格)应用于每个子字符串。第二个就是让列表变得简单，这就是[[1, 2], [3, 4]]将变成[1, 2, 3, 4]。它相当于：

the_list = ['Cisco IOS Software, C2960S Software (C2960S-UNIVERSALK9-M), Version 15.0(2)SE11, RELEASE SOFTWARE (fc3)', 'NAME: "1", DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L  , VID: V02  , SN: FOC1452X5C5\n\n']

new_list = []
for string in the_list:
    for item in string.split(','):
        new_list.append(item.strip())

Answer 2

看起来你需要str.split和list.extend

Ex:

myList1 = []        
for k in range(len(cli_commands)):
    net_connect.send_command(cli_commands[k])
    vall=net_connect.send_command(cli_commands[k])
    myList1.extend(vall.strip().split(","))
print(myList1)

Answer 3

绝对崩溃的答案是正确的，但你必须这样使用它

myList = ['Cisco IOS Software, C2960S Software (C2960S-UNIVERSALK9-M), Version 15.0(2)SE11, RELEASE SOFTWARE (fc3)', 'NAME: "1", DESCR: "WS-C2960S-24TS-L"\nPID: WS-C2960S-24TS-L  , VID: V02  , SN: FOC1452X5C5\n\n']

cs_mylist = []
for y in [x.split(',') for x in myList]:
    for z in y:
        cs_mylist.append(z)

print(cs_mylist)