迅速将新列附加到数组中

Question

我想逐行组织多维数组。我有一个函数，它从一个主数组创建了3个数组。我希望以列的形式将这些子数组添加到新数组中。

我尝试了以下几点：

/* Note

-subArray is a data structure where i have 3 values stored at each 
index index. these are named data1, data2, data3. I'm accessing them 
with the line chamberOne.append(thing.data1). this is referenced 
from tempCount's data. 

- data structure: 
at index # 1
 -data1
 -data1
 -data3

*/


static func subArray()->[String]
{
   var temp = mainArray[0...11]
   let tempCount = Array(temp)
   var returnArr: [String] = []

   var chamberOne: [String] = []
   for thing in tempCount
   {
      chamberOne.append(thing.data1)
   }
   // i have 2 more functions built the same as chamberOne, but they 
   //are named chamberTwo and chamberThree

   //as of right now I am appending like this
   returnArr + chamberOne + chamberTwo + chamberThree
  // this brings all the data into a single dimension array. 
}

我想要一种将chamberOne、chamberTwo和chamberThree追加为列或行的方法，这两种方法都可以，我只是希望通过在多维数组(returnArr)中添加一个一维数组(chamberOne)，将某种形式的组织形式添加到多维空间中。

Answer 1

假设有两个数组，如下所示：

var arr1 = ["a", "b", "c"]
var arr2 = ["1", "2", "3"]

现在，我们创建一个包含其他数组的数组，如：

var multiDimArray = [[String]]() //Array of subarrays

现在我们可以将这两个数组添加到multiDimArray中。

multiDimArray.append(arr1)
multiDimArray.append(arr2)

如果我们打印multiDimArray，就会得到[["a", "b", "c"], ["1", "2", "3"]]

如果我们需要第一个“行”，我们可以通过multiDimArray[0]获得它，这将给我们["a", "b", "c"]

Answer 2

如果我正确理解了你的问题，你需要一个[[String]]，又名Array of Arrays of String。下面是我将如何修改您的函数以解释这一点：

static func subArray() -> [[String]]
{
   var temp = mainArray[0...11]
   let tempCount = Array(temp)
   var returnArr: [[String]] = []

   var chamberOne: [String] = []

   for thing in tempCount
   {
      chamberOne.append(thing.data1)
   }

   returnArr.append(chamberOne)

   //Initialise chamberTwo and chamberThree here. Then append to the 2D array.
   returnArr.append(chamberTwo)
   returnArr.append(chamberThree)

   //The returnArr now looks like this [chamberOne, chamberTwo, chamberThree]
   returnArr
}