在下面的示例中,评估‘最佳团队’的最佳方法是什么?
| Winner In Event A | Winner In Event B |
|------------------- |------------------- |
| Bob | Alfred |
| Bob | Dave |
| Bob | Alfred |
| Jason | Alfred |
| John | Fred |
| Fred | John |
| John | Fred |
| Richard | Jason |
| Richard | Bob |在这种情况下,我希望它选择Fred & John,因为它们是配对3次,而不是与只配对2次的Bob和Alfred绑在一起。
在上面的例子中,我包含了标准的VLookup,我确信它是解决方案的关键,但我不确定配对版本是什么样子
发布于 2019-07-05 12:50:14
没有第三栏:
=INDEX(ARRAYFORMULA(QUERY(IF(LEN(A1:A&B1:B),
IF(A1:A>B1:B, A1:A&" & "&B1:B, B1:B&" & "&A1:A), ),
"select Col1,count(Col1) group by Col1 order by count(Col1) desc", 0)), 2, 1)

全表:
=ARRAYFORMULA(QUERY(IF(LEN(A1:A&B1:B),
IF(A1:A>B1:B, A1:A&" & "&B1:B, B1:B&" & "&A1:A), ),
"select Col1,count(Col1)
where Col1 is not null
group by Col1
order by count(Col1) desc
label count(Col1)''", 0))

发布于 2019-07-05 10:06:33
我理解了这一点,并将其放在上面的示例中,实质上创建了第三列,该列具有以下类型的值
=IF(A14>B14, A14&" & "&B14, B14&" & "&A14)这会让你觉得
| Winner In Event A | Winner In Event B | Ordered Team |
|------------------- |------------------- |----------------- |
| Bob | Alfred | Bob & Alfred |
| Bob | Dave | Dave & Bob |
| Bob | Alfred | Bob & Alfred |
| Jason | Alfred | Jason & Alfred |
| John | Fred | John & Fred |
| Fred | John | John & Fred |
| John | Fred | John & Fred |
| Richard | Jason | Richard & Jason |
| Richard | Bob | Richard & Bob |然后,您只需从第三列中数出最常见的值,当我使用谷歌时,这个值如下所示
=ARRAYFORMULA(INDEX(C14:C29,MATCH(MAX(COUNTIF(C14:C29,C14:C29)),COUNTIF(C14:C29,C14:C29),0)))https://stackoverflow.com/questions/56900435
复制相似问题