删除方括号内的内容，并从文本区域中删除换行符

Question

我有以下的文本区域在一个创建论坛贴子页。

There is some text here in front:

[confidential]
{sitedetails}

Site URL: aaa
Site Username: bbb
Site Password: cc

FTP URL: ddd
FTP Username: eee
FTP Password: ffff

Optional Information: gggg

{/sitedetails}
[/confidential]

There is some text in the middle. 

[confidential]
User added some confidential details. This should not be removed!!!
[/confidential]

And there is some text at the end.

当用户填写表单时，机密信息将自动粘贴到文本区域。但现在我想添加一个按钮，允许张贴没有网站的细节。但仍然允许机密信息。

就我个人而言，我不擅长正则表达式。看着那些，对我来说就像魔法一样。但我很确定这正是我所需要的。所以，我现在正在尝试下面的代码，但这是删除所有东西，但不随机。

var $editor = $(".markItUpEditor");
var curValue = $editor.val();
val = curValue;
val = val.replace(/'[confidential]'([\s\S]*)[\/confidential]/gm, "");
val = val.replace(/[[\]]/g,'')
$editor.val(val);
console.log(val);

我真的希望有人能帮我把这个部分从文本区域中删除，但保留其他的内容：

需要移除

[confidential]
{sitedetails}

Site URL: aaa
Site Username: bbb
Site Password: cc

FTP URL: ddd
FTP Username: eee
FTP Password: ffff

Optional Information: gggg

{/sitedetails}
[/confidential]

结果是这样的

There is some text here in front:

There is some text in the middle. 

[confidential]
User added some confidential details. This should not be removed!!!
[/confidential]

And there is some text at the end.

这些部分是需要删除的部分的开始和结束。请记住，文本区域中有分行符(输入)。

开始

[confidential]
{sitedetails}

结束

{/sitedetails}
[/confidential]

Answer 1

您想要的正则表达式是/\s*\[confidential\]\s*\{sitedetails\}(\s|\S)*{\/sitedetails\}\s*\[\/confidential\]\s*/g。

它有点冗长，但悬停在regex101的每个部分上，以了解发生了什么：https://regex101.com/r/R5Oece/1

但我很确定这正是我所需要的。

Regex很少是必要的，它是一个方便的工具，但是您也可以轻松地用新的行拆分文本，拼接出子数组，然后重新连接到一个字符串中。

​

    const str = `There is some text here in front:

[confidential]
{sitedetails}

Site URL: aaa
Site Username: bbb
Site Password: cc

FTP URL: ddd
FTP Username: eee
FTP Password: ffff

Optional Information: gggg

{/sitedetails}
[/confidential]

There is some text in the middle. 

[confidential]
User added some confidential details. This should not be removed!!!
[/confidential]

And there is some text at the end.`;

    let out = str.replace(/\s*\[confidential\]\s*\{sitedetails\}(\s|\S)*{\/sitedetails\}\s*\[\/confidential\]\s*/g, '\n\n');

    console.log(out);

​