从FTP数组返回的PHP排序列表

Question

我从ftp服务器以数组形式返回了文件：

Array
(
    [0] => FOLDER./Images.Vacation.2018
    [1] => ./Images.Vacation.2018/Racoon001.jpg
    [2] => ./Images.Vacation.2018/Racoon002.txt
    [3] => ./Images.Vacation.2018/the.racoon.swimming.mp4
    [4] => ./Images.Vacation.2018/the.racoon.swimming.slv
    [5] => FOLDER./WestImages
    [6] => ./WestImages/Ramco.txt
    [7] => ./WestImages/Ramco.jpg
    [8] => FOLDER./WestImages/Subimages
    [9] => ./WestImages/Subimages/Image001.jpg
    [10] => ./WestImages/Subimages/Image002.jpg
    [11] => ./WestImages/West.Ramco.Swimming.mp4
)

如您所见，SubImages在WestImages之前返回，这是wrong...so，我无法使用和

• 标签.我需要数组来返回这个： 数组( ./Images.Vacation.2018/the.racoon.swimming.mp4文件夹./Images.Vacation.2018 1 => ./Images.Vacation.2018/Racoon001.jpg 2 => ./Images.Vacation.2018/Racoon002.txt 3 => => 4 => 5 =>文件夹./WestImage 6 => ./WestImage/Ramco.txt 7 => ./WestImage/Ramco.jpg 8 => ./WestImage/West.Ramco.Swimming.mp4 9 =>文件夹./韦斯特图像/子图像10 => ./ => /子图像/Image001.jpg 11 =>./WestImage/Subimages/Image002.jpg) 这是我从服务器读取文件的ftp代码： /* contents ftp函数*/函数ftp_list_files_recursive($ftp_stream，$path){ $lines = ftp_rawlist($ftp_stream，$path)；$result = array()；foreach ($lines as $line){ $tokens =B爆发(“"，$line)；$name = $tokenscount($tokens) - 1；$type = $tokens；$type=。"/“。$name；if ($type == 'd'){ $result[] =‘result[]’. $filepath；$result = array_merge($result，ftp_list_files_recursive($ftp_stream，$filepath))；} /*内容- ftp */ $contents = ftp_list_files_recursive($conn_id，".")；echo‘；print_r($contents)；echo’； 我尝试使用sort($contents)；但是它返回错误的sorting...how来重写函数以返回正确的排序，就像上面给出的那样？ 谢谢。

Answer 1

这不是一个很好的解决方案，但是您可以使用preg_grep获取文件夹名，然后循环它们并对文件进行grep。

$folders = preg_grep("/^FOLDER.*/", $arr);

foreach($folders as $folder){
    $result[] = $folder;
    $result = array_merge($result, preg_grep("/^\." . str_replace(["FOLDER.", "/"], ["","\/"], $folder) . "\/[A-Za-z0-9\.]+$/", $arr));
}

var_dump($result);

https://3v4l.org/BthA0