我正在编写一些API,我希望在编写代码时集成文档,因此我发现Swagger是一种很好的方法。
我使用了Swagger核心v3符号,所以我的类如下所示:
@RestController
@RequestMapping("/api/v1/bundles")
@OpenAPIDefinition(
info = @Info(
title = "Lifecycle Management RESTful API.",
version = "1",
description = "TODO",
license = @License(name = "Apache 2.0", url = "xxx"),
contact = @Contact(url = "xxx", name = "xx", email = "xxx@xxx.fr")
))
public class RestBundle {
@GetMapping(value = "/{nodeId}",
produces = MediaType.APPLICATION_JSON_VALUE)
@ResponseStatus(HttpStatus.OK)
@ResponseBody
@Operation(summary = "Get all bundles",
description = "Get all available bundles status from a specific node")
public Something(..) {
//Something ...
}
}我创建了一个配置类:
@Configuration
@EnableSwagger2
public class SwaggerConfig {
@Bean
public Docket api() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.any())
.build()
.apiInfo(apiInfo());
}
ApiInfo apiInfo() {
return new ApiInfoBuilder()
.title("ANF Orchestrator")
.description("REST API for ANF Orchestrator")
.license("Apache 2.0")
.licenseUrl("http://www.apache.org/licenses/LICENSE-2.0.html")
.termsOfServiceUrl("")
.version("1.0.0")
.contact(new Contact("Amine","xxx", "aalaouie@laas.fr"))
.build();
}
}ANd我想让Swagger的UI获得文档,但是当我输入:./swagger-ui.html时
我得到:
无法呈现此定义,所提供的定义没有指定有效的版本字段。 请指定有效的Swagger或OpenAPI版本字段。支持的版本字段是swagger:"2.0“和那些匹配openapi: 3.0.n的字段(例如openapi: 3.0.0)。
发布于 2019-06-05 10:45:31
尝试用WebMvcConfigurationSupport扩展您的SwaggerConfig类,并使用如下实现覆盖它的方法addResourceHandlers:
@Override
protected void addResourceHandlers(ResourceHandlerRegistry registry) {
registry.addResourceHandler("swagger-ui.html")
.addResourceLocations("classpath:/META-INF/resources/");
registry.addResourceHandler("/webjars/**")
.addResourceLocations("classpath:/META-INF/resources/webjars/");
}发布于 2019-06-05 12:11:00
在类的顶部,您是否可以尝试删除这个注释,因为SwaggerConfig已经包含了文档信息。
@OpenAPIDefinition(
info = @Info(
title = "Lifecycle Management RESTful API.",
version = "1",
description = "TODO",
license = @License(name = "Apache 2.0", url = "xxx"),
contact = @Contact(url = "xxx", name = "xx", email = "xxx@xxx.fr")
))https://stackoverflow.com/questions/56458833
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