我有一个PictureBox1,它的sizemode设置为拉伸和PictureBox1。PictureBox1包含一个图像,让我选择其中的一部分,然后对其进行裁剪,并将裁剪后的部分存储在PictureBox2中。当sizemode被设置为拉伸,并且图片没有缩放时,它工作得很好,但是当我缩放它或将sizemode设置为缩放时,它就不能工作了。
用于裁剪图片部分的代码(原始源)
try
{
float stretch1X = 1f * pictureBox1.Image.Width / pictureBox1.ClientSize.Width;
float stretch1Y = 1f * pictureBox1.Image.Height / pictureBox1.ClientSize.Height;
Point pt = new Point((int)(_mDown.X * stretch1X), (int)(_mDown.Y * stretch1Y));
Size sz = new Size((int)((_mCurr.X - _mDown.X) * stretch1X),
(int)((_mCurr.Y - _mDown.Y) * stretch1Y));
if (sz.Width > 0 && sz.Height > 0)
{
Rectangle rSrc = new Rectangle(pt, sz);
Rectangle rDest = new Rectangle(Point.Empty, sz);
Bitmap bmp = new Bitmap(sz.Width, sz.Height);
using (Graphics G = Graphics.FromImage(bmp))
G.DrawImage(pictureBox1.Image, rDest, rSrc, GraphicsUnit.Pixel);
return bmp;
}
return null;
}
catch (Exception ex)
{
throw ex;
}我该如何正确计算?我如何使裁剪功能以某种方式工作,这样用户就可以放大/缩小图片的正确部分?
发布于 2019-05-29 14:12:39
你需要用拉伸因子和偏移量来计算点。
对于Zoom,只有一个因子,因为Image和PictureBox的纵横比总是相同的,但是通常有一个偏移量;对于Stretch,您不需要偏移量,只需要2<>E29因子。
下面是一个使用2 PictureBoxes 2的例子,它显示了一个缩放的版本和剪裁的位图。它利用了一个通用函数ImageArea来确定大小和偏移量.

两个类级变量:
Point pDown = Point.Empty;
Rectangle rect = Rectangle.Empty;三个鼠标事件:
private void PictureBox1_MouseDown(object sender, MouseEventArgs e)
{
pDown = e.Location;
pictureBox1.Refresh();
}
private void PictureBox1_MouseMove(object sender, MouseEventArgs e)
{
if (!e.Button.HasFlag(MouseButtons.Left)) return;
rect = new Rectangle(pDown, new Size(e.X - pDown.X, e.Y - pDown.Y));
using (Graphics g = pictureBox1.CreateGraphics())
{
pictureBox1.Refresh();
g.DrawRectangle(Pens.Orange, rect);
}
}
private void PictureBox1_MouseUp(object sender, MouseEventArgs e)
{
Rectangle iR = ImageArea(pictureBox2);
rect = new Rectangle(pDown.X - iR.X, pDown.Y - iR.Y,
e.X - pDown.X, e.Y - pDown.Y);
Rectangle rectSrc = Scaled(rect, pictureBox2, true);
Rectangle rectDest = new Rectangle(Point.Empty, rectSrc.Size);
Bitmap bmp = new Bitmap(rectDest.Width, rectDest.Height);
using (Graphics g = Graphics.FromImage(bmp))
{
g.DrawImage(pictureBox2.Image, rectDest, rectSrc, GraphicsUnit.Pixel);
}
pictureBox2.Image = bmp;
}下面是一个有用的函数,它返回任何sizemode的picturebox中的实际图像区域。
Rectangle ImageArea(PictureBox pbox)
{
Size si = pbox.Image.Size;
Size sp = pbox.ClientSize;
if (pbox.SizeMode == PictureBoxSizeMode.StretchImage)
return pbox.ClientRectangle;
if (pbox.SizeMode == PictureBoxSizeMode.Normal ||
pbox.SizeMode == PictureBoxSizeMode.AutoSize)
return new Rectangle(Point.Empty, si);
if (pbox.SizeMode == PictureBoxSizeMode.CenterImage)
return new Rectangle(new Point((sp.Width - si.Width) / 2,
(sp.Height - si.Height) / 2), si);
// PictureBoxSizeMode.Zoom
float ri = 1f * si.Width / si.Height;
float rp = 1f * sp.Width / sp.Height;
if (rp > ri)
{
int width = si.Width * sp.Height / si.Height;
int left = (sp.Width - width) / 2;
return new Rectangle(left, 0, width, sp.Height);
}
else
{
int height = si.Height * sp.Width / si.Width;
int top = (sp.Height - height) / 2;
return new Rectangle(0, top, sp.Width, height);
}
}我们只需要偏移量来确定不缩放的矩形。我们还需要扩大规模:
Rectangle Scaled(Rectangle rect, PictureBox pbox, bool scale)
{
float factor = GetFactor(pbox);
if (!scale) factor = 1f / factor;
return Rectangle.Round(new RectangleF(rect.X * factor, rect.Y * factor,
rect.Width * factor, rect.Height * factor));
}为此,需要知道比例因子,这取决于高宽比:
float GetFactor(PictureBox pBox)
{
if (pBox.Image == null) return 0;
Size si = pBox.Image.Size;
Size sp = pBox.ClientSize;
float ri = 1f * si.Width / si.Height;
float rp = 1f * sp.Width / sp.Height;
float factor = 1f * pBox.Image.Width / pBox.ClientSize.Width;
if (rp > ri) factor = 1f * pBox.Image.Height / pBox.ClientSize.Height;
return factor;
}如果PictureBox被放大或移出,将其放置在AutoScrolling Panel中并更改Pbox.Size,则此解决方案也能工作。
https://stackoverflow.com/questions/56360036
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