RxAlamofire与json主体进行post调用

Question

我想使用RxAlamofire进行post调用，但找不到任何方法。

尝试使用requestJSON方法，但没有参数来传递后置json

 RxAlamofire.requestJSON(.post, url)

如何在RxAlamofire中进行post调用并将json数据传递给post调用

Answer 1

使用下列代码

  var request = URLRequest(url: URL(string: "https://some_url")!)
    //Following code to pass post json 
    request.httpBody = json
    request.httpMethod = "POST"
    request.setValue("application/json", forHTTPHeaderField: "Content-Type")
    RxAlamofire.request(request as URLRequestConvertible).responseJSON().asObservable()

Answer 2

在适当的参数和编码条件下使用此函数

public func urlRequest(_ method: Alamofire.HTTPMethod,
                   _ url: URLConvertible,
                   parameters: [String: Any]? = nil,
                   encoding: ParameterEncoding = URLEncoding.default,
                   headers: [String: String]? = nil)

Answer 3

amodkanthe的解决方案有效。但它的回报价值并不是很好。所以我把它改了一点

    var request = URLRequest(url: URL(string: "https://some_url")!)
    request.httpBody = jsonData  // jsonData is a Data type
    request.httpMethod = "POST"
    request.setValue("application/json", forHTTPHeaderField: "Content-Type") // this line is important
    RxAlamofire.requestJSON() //=> returns a Observable<(HttpURLResponse, Any)>, the `Any` type is actually a dictionary

附注：我使用的版本是RxAlamofire(6.1.1)