我正在开发mysql服务器中的数据库视图,通过将grns加入注释表来获取grns的状态。我想显示grn被拒绝或批准。对于注释表上的单个grns,可能有几个注释。
如果grn的注释表状态中有一个grn的“批准”,则必须以“已批准”的形式返回,否则“拒绝”或“待定”,这里是两个表的虚拟。

预期成果:
G1 - rejected
G2 - approved
G3 - approved
G4 - approved
G5 - approved发布于 2019-05-16 13:07:34
可以通过测试comment中是否存在每个grn-no值具有approved或rejected状态的行来完成这一任务。如果grn既未被批准,也未被拒绝,则状态设置为pending。
SELECT g.`grn-no`,
CASE WHEN EXISTS (SELECT * FROM comment c WHERE c.grn_id = g.id AND c.status = 'approved') THEN 'approved'
WHEN EXISTS (SELECT * FROM comment c WHERE c.grn_id = g.id AND c.status = 'rejected') THEN 'rejected'
ELSE 'pending' END AS status
FROM grn g 输出:
grn-no status
G1 rejected
G2 approved
G3 approved
G4 approved
G5 approved发布于 2019-05-16 17:10:49
您可以使用group_concat(flatten)函数
Select
`grn-no`,
Case when status like ('%approved%') then 'approved' else 'rejected' end as status
From
(Select
`grn-no`,
group_concat(status) as status
From grn
left join comment
on grn.id = comment.grn_id
group by 1) a发布于 2019-06-29 08:57:20
最后,我发现了上述代码后面的所有函数。上面的问题是开发下面的数据库视图。
CREATE OR REPLACE VIEW summery AS
SELECT
g.id,
g.supply_date,
g.grn_no,
COUNT(b.bag_no) AS bags,
CONCAT(s.fname," ", s.lname) AS name,
SUM(b.weight) AS qty,
AVG(b.bag_mc) AS mc,
(g.dust_initial/g.dust_weight)*100 AS dust,
(g.ubs_initial/g.ubs_weight)*100 AS ubs,
p.fraction_1 AS fraction_1,
CASE
WHEN EXISTS (SELECT * FROM comments c WHERE c.grn_id = g.id AND c.status = 'approved') THEN 'Approved'
WHEN EXISTS (SELECT * FROM comments c WHERE c.grn_id = g.id AND c.status = 'approved with concession') THEN 'Approved with Concession'
WHEN EXISTS (SELECT * FROM comments c WHERE c.grn_id = g.id AND c.status = 'concession required') THEN 'Concession Required'
WHEN EXISTS (SELECT * FROM comments c WHERE c.grn_id = g.id AND c.status = 'rejected') THEN 'Rejected'
ELSE 'pending' END AS status
FROM grns g
JOIN suppliers s ON s.id = g.supplier_id
JOIN psds p ON g.id = p.grn_id
JOIN bags b ON g.id = b.grn_id
GROUP BY g.id
ORDER BY g.id DESChttps://stackoverflow.com/questions/56169202
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