短语后面的捕获号

Question

我有这样的条件：

1. 你的签约奖金是123,000
2. 今年的签约奖金很糟糕。今年的签约奖金是12.3万欧元。
3. 奖金为14456英镑，但签约奖金。

我想要的输出如下：

如果有任何数字紧跟在signing bonus后面，则保留字符串的该部分并删除所有内容。见预期输出1& 2

( b)如果没有数字后面跟着signing bonus，我应该得到第一部分的刺。见预期输出3

预期输出

1. 是123,000
2. 今年是12.3万欧元。
3. 奖金是14,456，但是

My Regex:

match1 = re.findall(r'(?<=\bSigning Bonus\b)\s*(?:\S+\b\s*){0,8}',value, re.I|re.M|re.DOTALL)

处理输出1和输出2，但不能处理输出3.

我也是开放的解决方案，可以不需要正则！

Answer 1

如果您可以使用re.sub，那么您可以使用这个正则表达式用空字符串替换匹配的文本，

^[^\d\n]*signing bonus\s*|\s*signing bonus[^\d\n]*$

在前两种情况下，您打算在signing bonus之后捕获字符串，但在第三种情况下，您的预期字符串在signing bonus之前，因此需要使用交替的另一个正则表达式。

Regex Demo

Python代码，

import re

arr = ['Your signing bonus is 123,000','This year signing bonus is bad. the signing bonus for this year is EUR 123,000','The bonus is 14,456, but signing bonus.']

for s in arr:
 print(s, '-->', re.sub(r'^[^\d\n]*signing bonus\s*|\s*signing bonus[^\d\n]*$', '', s))

指纹，

our signing bonus is 123,000 --> is 123,000
This year signing bonus is bad. the signing bonus for this year is EUR 123,000 --> for this year is EUR 123,000
The bonus is 14,456, but signing bonus. --> The bonus is 14,456, but

Answer 2

试试下面的代码。

s1 = "Your signing bonus is 123,000"
s2 = "This year signing bonus is bad. the signing bonus for this year is EUR 123,000"
s3 = "The bonus is 14,456, but signing bonus."
regex = '[0-9]'
import re
def format_string(s):
    for subs in s.split('signing bonus'):
        if re.findall(regex, subs):
            print subs.strip()

format_string(s1)
format_string(s2)
format_string(s3)

产出如下：

is 123,000
for this year is EUR 123,000
The bonus is 14,456, but

Answer 3

这将打印出你的答案：

statements = [
    'Your signing bonus is 123,000',
    'This year signing bonus is bad. the signing bonus for this year is EUR 123,000',
    'The bonus is 14,456, but signing bonus.',
]
for statement in statements:
    ans = statement.split('signing bonus')
    if not ans:
        print('')
        continue
    for i in range(len(ans) - 1, -1, -1):
        for word in ans[i].split(' '):
            try:
                number = int(word.replace(',', ''))
                print(ans[i].strip())
                break
            except:
                pass

输出：

is 123,000
for this year is EUR 123,000
The bonus is 14,456, but